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Question: How do you sketch the graph of \[y = {\left( {x - 3} \right)^2}\] and describe the transformation?...

How do you sketch the graph of y=(x3)2y = {\left( {x - 3} \right)^2} and describe the transformation?

Explanation

Solution

Here we have to show the graphical representation of y=(x3)2y = {\left( {x - 3} \right)^2} . To do so, our first approach is to find different values of yy for the different values of xx . Then, we will plot the obtained points on a graph. Therefore we can sketch the graph of y=(x3)2y = {\left( {x - 3} \right)^2} by joining all the points with a curved line. Also, in the given equation y=(x3)2y = {\left( {x - 3} \right)^2} , the R.H.S. is whole squared which means that yy will always be a non-negative number. Therefore, for all values of xx , the graph will lie above the x-axis, i.e. in the first and second quadrant.

Complete step by step answer:
Given equation is y=(x3)2y = {\left( {x - 3} \right)^2} .
Now we have to find different coordinates which satisfy the equation, i.e. those points which lie on the above curve.
Hence, we will put random values for xx and find the related value of yy for that xx or vice-versa.
Now, putting the value x=0x = 0 in the equation y=(x3)2y = {\left( {x - 3} \right)^2} ,
We get,
y=(03)2y = {\left( {0 - 3} \right)^2}
y=(3)2y = {\left( { - 3} \right)^2}
Solving the R.H.S., we get
y=9y = 9
Therefore, y=9y = 9 for x=0x = 0 .
Similarly, putting the value y=0y = 0 in y=(x3)2y = {\left( {x - 3} \right)^2}
We get,
0=(x3)20 = {\left( {x - 3} \right)^2}
Taking square root of both sides,
x3=0x - 3 = 0
Adding 3 both sides, we get
x=3x = 3
Therefore, x=3x = 3 for y=0y = 0
Again, putting the value x=4x = 4 in the equation y=(x3)2y = {\left( {x - 3} \right)^2}
We get,
y=(43)2y = {\left( {4 - 3} \right)^2}
Solving the R.H.S., we get
y=(1)2y = {\left( 1 \right)^2}
or
y=1y = 1
Therefore, y=1y = 1 for x=4x = 4
Now the three obtained points are:

xx003344
yy990011

Therefore, the three coordinates that lie on the curve y=(x3)2y = {\left( {x - 3} \right)^2} are (0,9)\left( {0,9} \right) , (3,0)\left( {3,0} \right) and (4,1)\left( {4,1} \right) .
Plotting these points on a graph and then extending the curve after joining all the points gives us the graph of y=(x3)2y = {\left( {x - 3} \right)^2} .
The obtained graph is shown below:

That is the required graphical representation of the equation y=(x3)2y = {\left( {x - 3} \right)^2} .
When the equation is given in its particular form as y=(xa)2y = {\left( {x - a} \right)^2} , then the curve is shifted by aa units on the x-axis. In that case, the point of contact of the curve and the x-axis is (a,0)\left( {a,0} \right) . For example, in the above equation y=(x3)2y = {\left( {x - 3} \right)^2} , the curve was shifted by 33 units on the x-axis.

Note:
The standard form of such curves is y=x2y = {x^2} . That curve also looks similar to the curve in the above graph but the curve touches the x-axis at the origin (0,0)\left( {0,0} \right) . The given graph depicts an upward facing parabola touching the x axis at (3,0)\left( {3,0} \right).