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Question: How do you sketch the graph of \(f\left( x \right) = \arccos \left( x \right)\) ?...

How do you sketch the graph of f(x)=arccos(x)f\left( x \right) = \arccos \left( x \right) ?

Explanation

Solution

A graph of a function f is the set of ordered pairs; the equation of graph is generally represented as y=f(x)y = f\left( x \right) , where x and f(x) are real numbers. We substitute the value of x and we determine the value of y and then we mark the points in the graph and we join the points.

Complete step by step answer:
Here in this question, we have to plot the graph for the given function. A graph of a function is a set of ordered pairs and it is represented as y=f(x)y = f\left( x \right), where x and f(x) are real numbers. These pairs are in the form of Cartesian form and the graph is the two-dimensional graph.
First, we have to find the value of y by using the equation of function y=f(x)=arccos(x)y = f\left( x \right) = \arccos \left( x \right). Let us substitute the value of x has 1 - 1, 00, and 11.
Now we consider the value of x as 1 - 1, the value of y is
y=arccos(1)\Rightarrow y = \arccos \left( { - 1} \right)
y=π\Rightarrow y = \pi
Now we consider the value of x as 00, the value of y is
y=arccos(0)\Rightarrow y = \arccos \left( 0 \right)
y=π2\Rightarrow y = \dfrac{\pi }{2}
Now we consider the value of x as 11, the value of y is
y=arccos(1)\Rightarrow y = \arccos \left( 1 \right)
y=0\Rightarrow y = 0
Now we draw a table for these values we have

x00111 - 1
yπ2\dfrac{\pi }{2}00π\pi

The graph plotted for this point is represented below:

Note: The graph is plotted x-axis versus y axis. The graph is two dimensional. By the equation of a graph, we can plot the graph by assuming the value of x. We can’t assume the value of y. because the value of y depends on the value of x. Hence, we have plotted the graph.