Question
Question: How do you simplify \[\tan {{25}^{\circ }}\cot {{25}^{\circ }}\]?...
How do you simplify tan25∘cot25∘?
Solution
Assume the given expression as ‘E’. Consider a right-angle triangle and assume any one of the two acute angles as θ. Consider the trigonometric ratio tanθ and cotθ assuming the side opposite to the angle θ as the perpendicular, the other side as the base and the side opposite to the angle 90∘ as the hypotenuse. Find the value of tanθ×cotθ and use it to get the value of the provided expression.
Complete step by step solution:
Here, we have been provided with the expression tan25∘cot25∘ and we are asked to simplify it. Let us know the given expression as ‘E’, so we have,
⇒E=tan25∘cot25∘
Since, we don’t know the value of the tangent and cotangent function for the angle 25∘, so we need to use some other approach to get the answer. Let us see if we can derive a formula for the product of the tangent and cotangent function.
In the above figure we have assumed a right-angled triangle at B. Angle C is considered as θ, so the side AB will be the perpendicular, BC as the base and AC as the hypotenuse. We know that the tangent function is the ratio of perpendicular to the base while cotangent function is the ratio of base to the perpendicular, so mathematically we have,
⇒tanθ=BCAB=bp - (1)
⇒cotθ=ABBC=pb - (2)
Multiplying the above two equations, we get,
⇒tanθ×cotθ=bp×pb
Cancelling the common terms, we get,
⇒tanθ×cotθ=1
Therefore, the value of the product of the tangent and cotangent function is always 1 for the same angle, irrespective of the value of θ. So, substituting θ=25∘, we get,