Question
Question: How do you simplify: \(\sin \left( {x + \dfrac{\pi }{4}} \right)\) ?...
How do you simplify: sin(x+4π) ?
Solution
The given question deals with basic simplification of trigonometric functions by using some of the simple trigonometric formulae such as the compound angle formulae for sine function sin(A+B)=sinAcosB+cosAsinB. Basic algebraic rules and trigonometric identities are to be kept in mind while doing simplification in the given problem.
Complete answer:
In the given problem, we have to simplify the trigonometric expression given to us as: sin(x+4π)
So, we will use the compound angle formula for sine function as sin(A+B)=sinAcosB+cosAsinB where A=x and B=(4π). Hence, we get the expanded form as,
⇒sin(x+4π)=sinxcos(4π)+cosxsin(4π)
Now, we have to substitute in the values of cosine and sine function for the angle (4π) and then get the simplified form of the trigonometric expression.
We know that the value of cosine function for the standard angle (4π) is cos(4π)=21 and value of sine function for the same angle is sin(4π)=21.
So, we get,
⇒sin(x+4π)=sinx(21)+cosx(21)
Now, taking the common terms outside the brackets, we get,
⇒sin(x+4π)=(21)(sinx+cosx)
Hence, the simplified form of the trigonometric expression sin(x+4π) can be simplified as (21)(sinx+cosx) by the use of basic algebraic rules and simple trigonometric formulae.
Note:
Trigonometric functions are also called Circular functions. Trigonometric functions are the functions that relate an angle of a right angled triangle to the ratio of two side lengths. There are 6trigonometric functions, namely: sin(x),cos(x),tan(x),cosec(x),sec(x)and cot(x) . We must know the compound angle formulae of sine as sin(A+B)=sinAcosB+cosAsinB and cosine as cos(A+B)=cosAcosB−sinAsinB.