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Question: How do you simplify \({\left( {\dfrac{{25}}{{16}}} \right)^{ - \dfrac{3}{2}}}\)?...

How do you simplify (2516)32{\left( {\dfrac{{25}}{{16}}} \right)^{ - \dfrac{3}{2}}}?

Explanation

Solution

In order to determine the simplest form of the above question ,first take the reciprocal to remove negative sign from the exponent and then write 16=42and25=5216 = {4^2}\,and\,25 = {5^2} and divide the exponents using identity (am)1n=amn{\left( {{a^m}} \right)^{\dfrac{1}{n}}} = {a^{\dfrac{m}{n}}} to get your required simplification.

Complete step by step solution:
We are given a rational number (2516)32{\left( {\dfrac{{25}}{{16}}} \right)^{ - \dfrac{3}{2}}}.
In order to simplify the above rational number we will be using some of the exponential identities ,to rewrite the rational number and simplify it.
Since, any number raised to negative power , is actually the reciprocal of it .
Taking the reciprocal of our given function to remove the negative sign from the exponent value .

=(2516)32 =(1625)32 = {\left( {\dfrac{{25}}{{16}}} \right)^{ - \dfrac{3}{2}}} \\\ = {\left( {\dfrac{{16}}{{25}}} \right)^{\dfrac{3}{2}}} \\\

Using exponential identity which state amn=(am)1n{a^{\dfrac{m}{n}}} = {\left( {{a^m}} \right)^{\dfrac{1}{n}}} by consider m as 3 and n as 2, we get
=((1625)3)12= {\left( {{{\left( {\dfrac{{16}}{{25}}} \right)}^3}} \right)^{\dfrac{1}{2}}}
Power get split into numerator and denominator if a power exist for some fraction
=(163253)12= {\left( {\dfrac{{{{16}^3}}}{{{{25}^3}}}} \right)^{\dfrac{1}{2}}}
Since,163=46{16^3} = {4^6}and 253=56{25^3} = {5^6}

=(4656)12 =462562 =4353 =64125 = {\left( {\dfrac{{{4^6}}}{{{5^6}}}} \right)^{\dfrac{1}{2}}} \\\ = \dfrac{{{4^{\dfrac{6}{2}}}}}{{{5^{\dfrac{6}{2}}}}} \\\ = \dfrac{{{4^3}}}{{{5^3}}} \\\ = \dfrac{{64}}{{125}} \\\

Therefore, (2516)32{\left( {\dfrac{{25}}{{16}}} \right)^{ - \dfrac{3}{2}}}in the simplest form is equal to
64125\dfrac{{64}}{{125}}
Additional Information:
What is a Rational Number?
A Rational number is a number which can be expressed in the form of pq\dfrac{p}{q}, where p and q are any integer value and q is not equal to 0. Such a number is known as a rational number.

Note:
1. If you want to Increase a Number by y %:
Example: On the off chance that a number is expanded by10 %10{\text{ }}\% , at that point it becomes 1.1 times of itself.
On the off chance that a number is expanded by 30%, at that point it becomes 1.3 times of itself.
2. If you want to Decrease a Number by y %:
Example: On the off chance that a number is diminished by 10%, at that point it becomes 0.90 times of itself.
On the off chance that a number is diminished by 30%, at that point it becomes 0.70 times of itself.
3. Value of the constant ”e” exponent is equal to 2.71828.
4. Don’t forget to cross check your result.