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Question

Question: How do you simplify \[{\left( {125} \right)^{\dfrac{1}{3}}}\]?...

How do you simplify (125)13{\left( {125} \right)^{\dfrac{1}{3}}}?

Explanation

Solution

In order to write the expression into the simplest form, factorize the base part of the value inside the bracket as53{5^3} and the property of exponents that(am)n=am×n{({a^m})^n} = {a^{m \times n}}to find the desired answer.

Formula Used:
(a)mn{(a)^{\dfrac{m}{n}}}=(am)1n{({a^m})^{\dfrac{1}{n}}}
xm+n=xm×xn{x^{m + n}} = {x^m} \times {x^n}

Complete step by step solution:
Given a number
(125)13{\left( {125} \right)^{\dfrac{1}{3}}}

Separating the value 125125 into its factors, So the factors of 125125 comes to be,
1,5,25,1251,5,25,125

Now let’s find the factors who are perfect cubes
1,51,5

From the above we can say that 125=5×5×5125 = 5 \times 5 \times 5
Replace 125125as 5×5×55 \times 5 \times 5 in the original number

=(5×5×5)13 =(53)13 = {\left( {5 \times 5 \times 5} \right)^{\dfrac{1}{3}}} \\\ = {({5^3})^{\dfrac{1}{3}}} \\\

Using proper of exponents (am)n=am×n{({a^m})^n} = {a^{m \times n}}

=53×13 =5 = {5^{3 \times \dfrac{1}{3}}} \\\ = 5 \\\

Therefore, (125)13{\left( {125} \right)^{\dfrac{1}{3}}}in the simplest form is equal to 55.

Additional Information: 1. To calculate fraction from the percentage, divide the given percentage value by 100

For example: We have to write 70%70\% into fraction
$

= \dfrac{{70}}{{100}} \\
= \dfrac{7}{{10}} \\
Or Or = 0.7$

2. If you want to Increase a Number by y %:
Example: On the off chance that a number is expanded by10 %10{\text{ }}\% , at that point it becomes 1.1 times of itself.

On the off chance that a number is expanded by 30 %, at that point it becomes 1.3 times of itself.

3. If you want to Decrease a Number by y %:
Example: On the off chance that a number is diminished by 10 %, at that point it becomes 0.90 times of itself.

On the off chance that a number is diminished by 30 %, at that point it becomes 0.70 times of itself.

Note: 1. Don’t Forgot to cross check the answer.
2.Factorise the number inside the square root properly to get knowledge of every perfect square