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Question: How do you simplify \(7x+4\left( x+5 \right)\)?...

How do you simplify 7x+4(x+5)7x+4\left( x+5 \right)?

Explanation

Solution

We separate the variables and the constants of the equation 7x+4(x+5)7x+4\left( x+5 \right). We apply the binary operation of addition and subtraction for both variables and constants. The solutions of the variables and the constants will be added at the end to get the final answer. We can also solve the simplified form of the expression for the given value of aa and find the value of the variable xx.

Complete step by step solution:
The given equation 7x+4(x+5)7x+4\left( x+5 \right) is an algebraic expression of xx. We need to simplify the equation by solving the variables and the constants separately.

All the terms in the equation of 7x+4(x+5)7x+4\left( x+5 \right) are either variable of xx or a constant. We
first separate the variables.

We break the multiplication by multiplying 4 with (x+5)\left( x+5 \right).
4(x+5)=4x+204\left( x+5 \right)=4x+20. The expression change from 7x+4(x+5)7x+4\left( x+5 \right) to 7x+4x+207x+4x+20

There are two variables which are 7x7x and 4x4x.

The binary operation between them is addition which gives us 7x+4x=11x7x+4x=11x.

Now we take the constants.

There is only one constant which is 20.

The final solution becomes
7x+4(x+5) =7x+4x+20 =11x+20 \begin{aligned} & 7x+4\left( x+5 \right) \\\ & =7x+4x+20 \\\ & =11x+20 \\\ \end{aligned}.

Now if we had to find the solution of the given equation being equal to aa, then the equation
becomes 11x+20=a11x+20=a. Here aa is constant.

Now we take the variable on one side and the constants on the other side.

& 11x+20=a \\\ & \Rightarrow 11x=a-20 \\\ & \Rightarrow x=\dfrac{a-20}{11} \\\ \end{aligned}$$ Therefore, the solution is $$x=\dfrac{a-20}{11}$$. **Therefore, the simplified form of the expression $7x+4\left( x+5 \right)$ is $11x+20$.** **Note:** We can verify the result of the equation $7x+4\left( x+5 \right)=11x+20$ by taking the value of $x$ as $x=2$. Therefore, the left-hand side of the equation becomes $7x+4\left( x+5 \right)=7\times 2+4\left( 2+5 \right)=14+4\times 7=42$ the right-hand side of the equation becomes $11x+20=11\times 2+20=22+20=42$ Thus, verified for the equation $7x+4\left( x+5 \right)=11x+20$.