Question
Question: How do you simplify \[7i\times 3i\times \left( -8-6i \right)\]?...
How do you simplify 7i×3i×(−8−6i)?
Solution
To simplify the given complex numbers, we need to multiply the imaginary numbers which are present outside the brackets with the imaginary number with complex numbers which are present inside the brackets. Then, we will get the answer to the given question.While solving we will use the value i2=−1 of the complex number for the given problem.
Complete step-by-step solution:
According to the question, we have been asked to simplify the given complex number 7i×3i×(−8−6i).
To solve this question, we will start with multiplying the imaginary numbers outside the bracket.
For simplification, we will multiply the numbers and i separately. That is, we have to multiply 7 with 3 and i with i. So, we can get 21 for the multiplication of 7 & 3. In the same way, we get i2 for the multiplication of i and i. Mathematically, we can represent it as
⇒(7×3)(i×i)×(−8−6i)
And on further simplifications, we get
⇒21i2×(−8−6i)
We know that i2=−1 which is the property of imaginary number. Therefore, we get
⇒21(−1)×(−8−6i)
⇒−21×(−8−6i)
Now, we will apply the distributive property a(b+c)=ab+ac, in the term−21×(−8−6i). Therefore, we get
⇒((−21)×(−8))−((−21)×(6i))
And we can also write it as
⇒(168)+(126i)
It is as same as
∴168+126i
Hence, the answer for the simplification of the complex number 7i×3i×(−8−6i) is 168+126i.
Note: While solving this question, we need to be very careful we might make a calculation mistake and end up with an incorrect answer. Also, we can solve this question by first multiplying terms out of the brackets one by one with the terms inside the brackets.