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Question

Question: How do you simplify \((5 + 3i)(3 - i)\) ?...

How do you simplify (5+3i)(3i)(5 + 3i)(3 - i) ?

Explanation

Solution

To solve these questions, we have to simplify the given expression. The expression can be simplified by simply multiplying the terms given in the parenthesis with one another. On further simplification of the expression obtained after multiplying, we will get the required solution.

Complete step by step answer:
It is given that, (5+3i)(3i)(5 + 3i)(3 - i)
To simplify the given expression, we need to multiply the terms given in the parenthesis with each other.
Let us multiply the second expression with the first and second term of the first expression, to get
(5+3i)(3i)=5(3i)+3i(3i)(5 + 3i)(3 - i) = 5(3 - i) + 3i(3 - i)
On multiplying the terms we get
5×35×i+3i×3+3i×(i)\Rightarrow 5 \times 3 - 5 \times i + 3i \times 3 + 3i \times ( - i)
On simplifying the above expression we get
155i+9i3i2\Rightarrow 15 - 5i + 9i - 3{i^2}
Adding the like terms that contain ii we get
154i3i2\Rightarrow 15 - 4i - 3{i^2}
In imaginary numbers, we know that the value of i2=1{i^2} = - 1 , where ii is an imaginary number. Therefore, by substituting the value i2{i^2} in the above expression we get
154i3(1)\Rightarrow 15 - 4i - 3( - 1)
154i+3\Rightarrow 15 - 4i + 3
Adding the terms we get
184i\Rightarrow 18 - 4i
Therefore, (5+3i)(3i)=184i(5 + 3i)(3 - i) = 18 - 4i

Hence on simplifying (5+3i)(3i)(5 + 3i)(3 - i) we get 184i18 - 4i

Additional information:
A complex number can be defined as a number that can be expressed in the form a+iba + ib where aa and bb are real numbers and ii represents the imaginary number and satisfies the equation i2=1{i^2} = - 1 . It also means that the value of ii is i=1i = \sqrt { - 1} . Since no real number satisfies the two given equations ii is called an imaginary number. Complex numbers cannot be marked on the number line.

Note: While solving these questions it is important to note down that complex numbers are represented in the form of a+iba + ib and that the imaginary part in this representation is bb and not   ib\;ib . Also, keep in mind to substitute the value of i2{i^2} in the expression to completely simplify the expression and then add the like terms.