Question
Question: How do you simplify \(3{x^2}y \times 4x{y^3}\)?...
How do you simplify 3x2y×4xy3?
Solution
We know that while calculating the product of two algebraic expressions we have to multiply the constants separately and variables separately. This will give us a product of two algebraic expressions. Let us assume the first algebraic expression is 3x2y and the second algebraic expression is 4xy3. Let us assume the constant part of 3x2y is equal to C1. Similarly, let us assume the constant part of 4xy3 is equal to C2. Now we have to find the product of C1 and C2. Let us assume this product as C3. Let us assume the variable part of 3x2y is equal to V1. Similarly, let us assume the constant part of 4xy3 is equal to V2. Now we have to find the product of V1 and V2. Let us assume this product as V3. Let us assume the product of given algebraic expressions is equal to C. Now we have to find the product of C3 and V3. This gives us the algebraic expression C.
Complete step-by-step answer:
Before solving the question, we should know that while calculating the product of two algebraic expressions we have to multiply the constants separately and variables separately. This will give us a product of two algebraic expressions.
From the question, we were given that to find the product of 3x2y,4xy3. Now we have to divide the given algebraic expressions into two parts. Let us consider the first algebraic expression as A. From the given question, it was given that the first algebraic expression is 3x2y.
First algebraic expression:
⇒A=3x2y ….. (1)
Now we have to divide the equation into two parts where the first part represents a constant and the second part indicates variables.
In equation (1), 3 is the constant part and x2y is the variable part.
Let us assume the constant part is equal to C1
⇒C1=3 ….. (2)
Let us assume the variable part is equal to V1
⇒V1=x2y ….. (3)
First algebraic expression:
⇒B=4xy3 ….. (4)
Now we have to divide the equation into two parts where the first part represents a constant and the second part indicates variables.
In equation (4), 4 is the constant part and xy3 is the variable part.
Let us assume the constant part is equal to C2
⇒C2=4 ….. (5)
Let us assume the variable part is equal to V2
⇒V2=xy3 ….. (6)
Now to find the product of the first algebraic expression and the second algebraic expression, we have to find the product of the constant parts of both algebraic expressions and the product of the variable parts of both algebraic expressions.
Let us assume the constant part of C is equal to C3.
Now we have to find the product of C1 and C2.
⇒C3=C1C2
Now we will substitute the value from equation (2) and equation (5) in the above equation, we get
⇒C3=3×4
Multiply the terms,
⇒C3=12 ….. (7)
Let us assume the constant part of C is equal to V3.
Now we have to find the product of V1 and V2.
⇒V3=V1V2
Now we will substitute the value from equation (3) and equation (6) in the above equation, we get
⇒V3=x2y×xy3
Multiply the terms,
⇒V3=x3y4 ….. (8)
We know that the product of the constant part of an algebraic expression and the variable part of an algebraic expression gives us the required algebraic expression.
Similarly, the product of the constant part of a C and the variable part of a C gives us the algebraic expression for C.
⇒C=C3V3
Now we have to substitute the value from equation (7) and equation (8), we get
⇒C=12×x3y4
Simplify the terms.
⇒C=12x3y4
Hence, the value is 12x3y4.
Note:
Algebraic expressions explain a set of operations that should be done following a specific set of orders. Such expressions consist of an amalgamation of integers, variables, exponents, and constants. When these expressions undergo the mathematical operation of multiplication, then the process is called the multiplication of algebraic expression. Two different expressions that give the same answer are called equivalent expressions. Some other properties like distributive and commutative property of addition will come in handy while doing multiplying polynomials. We will discuss the multiplication of algebraic expressions later, but first, we need to understand some terms used in algebra.