Question
Question: How do you prove that the diagonals of a rhombus are perpendicular?...
How do you prove that the diagonals of a rhombus are perpendicular?
Solution
Rhombus has all the four sides equal and opposite two sides of the rhombus are parallel to each other and the diagonals of the rhombus always intersect at right angles. Here first of all draw the figure of rhombus and diagonals.
Complete step by step solution:
Since in the above figure ABCD is a rhombus.
Therefore, all the four sides of the rhombus are equal.
∴AB=BC=CD=DA
In triangles ΔAOB and ΔCOB ,
OA=OC (Diagonals of the parallelogram bisect each other where bisection means two equal sections.)
OB=OB(Common Sides of the triangles)
AB=CB (Sides of the rhombus are equal)
∴ΔAOB≅ΔCOB(By SSS congruence rule)
By using Congruent part of the congruent triangle,
∠AOB=∠COB….. (I)
Also, AC is a line,
∠AOB+∠COB=180∘ (Linear pair)
By using the equation (I)
∠AOB+∠AOB=180∘
Simplify the above equation,
⇒2∠AOB=180∘
Term multiplicative on one side is moved to the opposite side, it goes to the denominator.
⇒∠AOB=2180∘
Common factors from the numerator and the denominator cancel each other.
⇒∠AOB=90∘
From equation (I),
∠AOB=∠COB ⇒∠AOB=90∘
Also,
Vertically opposite angles are equal to each other,
∠DOC=∠AOB=90∘
∠AOD=∠COB=90∘
Using above equations and its co-relations,
∠DOC=∠AOB=∠AOD=∠COB=90∘
⇒AC⊥BD
Therefore, diagonals of the rhombus are perpendicular to each other.
Note: Remember the difference between different types of the quadrilaterals and follow the properties accordingly. follow the different conditions of the congruence of the triangles to prove these types of solutions such as –
SSS criteria (Side - Side - Side)
SAS criteria (Side – Angle - Side)
ASA criteria (Angle – Side – Angle)
AAS criteria (Angle – Angle – Side)
RHS criteria (Right angle – Hypotenuse – Side)