Question
Question: How do you prove \[\dfrac{{\sin 2x}}{{1 + \cos 2x}} = \tan x\]?...
How do you prove 1+cos2xsin2x=tanx?
Solution
This question is related to the trigonometry, and we have to prove that the left hand side is equal to the right hand side of the expression, and this question can be solved by using trigonometric identities i.e.,sin2x=2sinxcosx and cos2x=2cos2x−1, and now by simplifying the expression that we will get by using the identities we will get the result which is on the right hand.
Complete step-by-step solution:
Given 1+cos2xsin2x=tanx,
Now we have to prove that left hand side is equal to the right hand side of the equation, now take the expression on the left hand side i.e.,
⇒1+cos2xsin2x,
Now using the trigonometric identities i.e., sin2x=2sinxcosx and cos2x=2cos2x−1,
Now we have cos2x=2cos2x−1,
By adding 1 to both sides of the identity, we get,
⇒2cos2x−1+1=1+cos2x,
Now eliminating like terms we get,
⇒2cos2x=1+cos2x,
Now substituting the identities in the left hand side of the given expression we get,
⇒1+cos2xsin2x=2cos2x2sinxcosx,
Now eliminating the like terms i.e., cosxand2 in both numerator and denominator, we get,
⇒1+cos2xsin2x=cosxsinx,
We know from the trigonometric identity cosxsinx=tanx, we get,
⇒1+cos2xsin2x=tanx,
Which is equal to the right hand side of the equation,
Hence proved.
∴By using identities we proved that expression 1+cos2xsin2x is equal to tanx.
Note: An identity is an equation that always holds true. A trigonometric identity is an identity that contains trigonometric functions and holds true for all right-angled triangles. They are useful when solving questions with trigonometric functions and expressions. There are many trigonometric identities, here are some useful identities:
sin2x=1−cos2x,
cos2x+sin2x=1,
sec2x−tan2x=1,
csc2x=1+cot2x.
cos2x−sin2x=1−2sin2x,
cos2x−sin2x=2cos2x−1,
sin2x=2sinxcosx,
2cos2x=1+cos2x,
tan2x=1−tan2x2tanx.