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Question: How do you name and draw 5 compounds that have the formula \( {C_7}{H_7}Br \) ?...

How do you name and draw 5 compounds that have the formula C7H7Br{C_7}{H_7}Br ?

Explanation

Solution

To know the name of compounds which have the formula C7H7Br{C_7}{H_7}Br , we should first write the general formula of the given formula, then we will discuss the five compounds which have the given formula.

Complete answer:
Well, you know that an alkane would have the general formula CnH2n+2{C_n}{H_{2n + 2}} , so this compound cannot be a straight-chained alkane.
That means you should try drawing alkenes and alkynes, and definitely try rings:-
∗* I tried a five-membered ring with two side-chain carbons, and added conjugated double bonds to decrease the number of hydrogens. That's one isomer.
∗* I tried drawing a six-membered ring with one side-chain carbon. When I placed a bromine on that carbon, I achieved C7H7Br{C_7}{H_7}Br . I moved the bromine onto the ring for another isomer, and moved that bromine around the ring for two more isomers for a total of five.

Seems like there are at least 14 though. If you want, three of them are bromene-ynes, which can be a challenge to name.
From left to right, top to bottom:
∗* 2−methyl−bromobenzene, or  o−bromotoluene, or 1−bromo−2−methylbenzene2 - methyl - bromobenzene,{\text{ }}or\;o - bromotoluene,{\text{ }}or{\text{ }}1 - bromo - 2 - methylbenzene
∗* 3−methyl−bromobenzene, or  m−bromotoluene, or 1−bromo−3−methylbenzene3 - methyl - bromobenzene,{\text{ }}or\;m - bromotoluene,{\text{ }}or{\text{ }}1 - bromo - 3 - methylbenzene
∗* 4−methyl−bromobenzene, or  p−bromotoluene, or 1−bromo−4−methylbenzene4 - methyl - bromobenzene,{\text{ }}or\;p - bromotoluene,{\text{ }}or{\text{ }}1 - bromo - 4 - methylbenzene
∗* I'm not sure how to name this one, so I looked it up and got:
\begin{array}{*{20}{l}} {5 - \left( {1 - bromoethylidene} \right) - 1,3 - cyclopentadiene} \\\ \; \end{array}
This uses cyclopentadiene as the parent compound, and an ethylidene substituent ( C=C∗−CH3C = \mathop C\limits^* - C{H_3} , with bromine on the starred carbon), and the upper-left carbon on cyclopentadiene is carbon-1; we'd move counter-clockwise.

Note:
Benzyl bromide is an organic compound with the formula C6H5CH2Br{C_6}{H_5}C{H_2}Br . The molecule consists of a benzene ring substituted with a bromomethyl group. It is a colorless liquid with lachrymatory properties.