Question
Question: How do you integrate \({e^{\sin x}}\cos xdx\) ?...
How do you integrate esinxcosxdx ?
Solution
In this question, we have been asked to integrate the given expression. In order to solve this question, use a substitution method. After substituting, differentiate the equation and put it in the given expression. The, integrate the resultant expression and put the assumed value in the answer.
Complete step-by-step solution:
We are given an expression and we have been asked to integrate it.
⇒∫esinxcosxdx …. (given)
We will solve this question using a substitution method as we can see that there is a trigonometric ratio in the power, whose differentiated value also exists in the given question itself. In such cases, we use substitution method
Let u=sinx ……….…. (1)
Differentiating both the sides with respect to x ,
dxdu=cosx
Shifting the denominator to the other side,
du=cosxdx ………...…. (2)
Putting equation (1) and equation (2) in the given equation,
⇒∫eudu
Now, we know that integration of ex is ex itself.
Using this,
⇒∫eudu=eu+C
Now, we will substitute u=sinx.
⇒esinx+C
Hence, ∫esinxcosxdx=esinx+C.
Note: In this question, we used the method of “Integration by Substitution”. This method is also known as the ‘u-Substitution’ or ‘The Reverse Chain Rule’ method. It is particularly used when the differentiation of the function, and the function – both are in the question together. It can be written as – ∫f(g(x))g′(x)dx
Here, we will substitute u=g(x) and then, we will differentiate it on both the sides with respect to x. We will get –
dxdu=g′(x)⇒du=g′(x)dx
Hence, if we substitute the results in the equation, our question now becomes,
∫f(u)du .
Thus, we have simplified our question. Make sure to find the answer in terms of x, and not in terms of u as u was not defined in the question and we generated it ourselves.