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Question

Question: How do you integrate \[\dfrac{{\tan x}}{{{{(\cos x)}^2}}}\]?...

How do you integrate tanx(cosx)2\dfrac{{\tan x}}{{{{(\cos x)}^2}}}?

Explanation

Solution

Here in this question, we have to integrate the given function. The function is in the form of trigonometry. First, we simplify the trigonometric function and then we are applying the integration to the function. Hence, we obtain the required solution for the question.

Complete step-by-step solution:
The function is related to the trigonometry and it includes the trigonometry ratios. The trigonometry ratios are sine, cosine, tangent, cosecant, secant and cotangent. In trigonometry the cosecant trigonometry ratio is the reciprocal to the sine trigonometry ratio. the secant trigonometry ratio is the reciprocal to the cosine trigonometry ratio and the cotangent trigonometry ratio is the reciprocal to the tangent trigonometry ratio.
The tangent trigonometry ratio is defined as tanx=sinxcosx\tan x = \dfrac{{\sin x}}{{\cos x}} , The cosecant trigonometry ratio is defined as cscx=1sinx\csc x = \dfrac{1}{{\sin x}}, The secant trigonometry ratio is defined as secx=1cosx\sec x = \dfrac{1}{{\cos x}} and The tangent trigonometry ratio is defined as cotx=cosxsinx\cot x = \dfrac{{\cos x}}{{\sin x}}
Now consider the given function tanx(cosx)2\dfrac{{\tan x}}{{{{(\cos x)}^2}}}, the secant trigonometry ratio is defined as secx=1cosx\sec x = \dfrac{1}{{\cos x}}. Now the function is written as
tanx(secx)2\Rightarrow \tan x{(\sec x)^2}
The squaring of a trigonometry ratio is written as
tanxsec2x\Rightarrow \tan x{\sec ^2}x
Now we apply the integration to the function
tanxsec2xdx\Rightarrow \int {\tan x{{\sec }^2}x} \,dx
Let we substitute u=tanxu = \tan x, then du=sec2xdx \Rightarrow du = {\sec ^2}x\,dx. Therefore the function is written as
udu\Rightarrow \int {u\,du}
On integrating
u22+C\Rightarrow \dfrac{{{u^2}}}{2} + C, where C is the integration constant.
Substituting the value of u,
tan2x2+C\Rightarrow \dfrac{{{{\tan }^2}x}}{2} + C
Hence we have integrated the given trigonometric function and obtained the solution.

Thus the final answer of the solution is tan2x2+C\dfrac{{{{\tan }^2}x}}{2} + C

Note: While integrating the trigonometric functions, we simplify the trigonometric functions as much as possible by using the trigonometry ratios or by trigonometry identities. The integration by substitution is the easiest way to integrate. The function and its derivative must be present while substituting.