Solveeit Logo

Question

Question: How do you graph \(y=\left| 2x+3 \right|\)?...

How do you graph y=2x+3y=\left| 2x+3 \right|?

Explanation

Solution

In this problem we need to draw the graph of the given equation y=2x+3y=\left| 2x+3 \right|. We can observe that the given equation is in modulus i.e., it will give only positive values of yy from the both the equations y=2x+3y=2x+3, y=2x3y=-2x-3. So, we will draw the graphs of the both the lines y=2x+3y=2x+3, y=2x3y=-2x-3 and we will consider only positive part of the both lines to show the graph of y=2x+3y=\left| 2x+3 \right|. To draw the graphs of the lines y=2x+3y=2x+3, y=2x3y=-2x-3, we will first assume y=0y=0 and calculates the value of xx and mark the points (x1,0)\left( {{x}_{1}},0 \right), (x2,0)\left( {{x}_{2}},0 \right) on the graph paper. Now we will assume x=0x=0 and calculates the value of yy and mark the points (0,y1)\left( 0,{{y}_{1}} \right), (0,y2)\left( 0,{{y}_{2}} \right) on the graph paper. Now the line that joins the points (x1,0)\left( {{x}_{1}},0 \right), (0,y1)\left( 0,{{y}_{1}} \right) will represent the line y=2x+3y=2x+3 and the line that joins the points (x2,0)\left( {{x}_{2}},0 \right), (0,y2)\left( 0,{{y}_{2}} \right) will represent the line y=2x3y=-2x-3. After plotting the graphs of the lines y=2x+3y=2x+3, y=2x3y=-2x-3 we will eliminate the part of the graphs which is in negative of yy to show the graph of y=2x+3y=\left| 2x+3 \right|.

Complete step-by-step solution:
Given equation, y=2x+3y=\left| 2x+3 \right|.
We can write the equation y=2x+3y=2x+3, y=2x3y=-2x-3 from the above given equation.
Substituting y=0y=0 in the both equation and simplifying them, then we will get
0=2x+3 3=2x x=1.5 \begin{aligned} & 0=2x+3 \\\ & \Rightarrow -3=2x \\\ & \Rightarrow x=-1.5 \\\ \end{aligned} and 0=2x3 2x=3 x=1.5 \begin{aligned} & 0=-2x-3 \\\ & \Rightarrow 2x=-3 \\\ & \Rightarrow x=-1.5 \\\ \end{aligned}
Now the point (1.5,0)\left( -1.5,0 \right) lies on both the equations.
Substituting x=0x=0 in the both equation and simplifying them, then we will get
y=2(0)+3 y=3 \begin{aligned} & y=2\left( 0 \right)+3 \\\ & \Rightarrow y=3 \\\ \end{aligned} and y=2(0)3 y=3 \begin{aligned} & y=-2\left( 0 \right)-3 \\\ & \Rightarrow y=-3 \\\ \end{aligned}
So, the point (0,3)\left( 0,3 \right) lies on y=2x+3y=2x+3, the point (0,3)\left( 0,-3 \right) lies on the line y=2x3y=-2x-3.
Plotting the points on a graph paper and joining (1.5,0)\left( -1.5,0 \right), (0,3)\left( 0,3 \right) to get the line y=2x+3y=2x+3 as well as joining the points (1.5,0)\left( -1.5,0 \right), (0,3)\left( 0,-3 \right) to get the line y=2x3y=-2x-3.

Now eliminating or neglecting the part of the graph which in negative yy to get the graph of y=2x+3y=\left| 2x+3 \right|.

The above graph is our required graph.

Note: In the problem we have the equation like y=2x+3y=\left| 2x+3 \right|, so we have followed the above method. Instead of giving y=2x+3y=\left| 2x+3 \right| if they have given y=2x+3y=2x+3 or y=2x3y=-2x-3, then we will calculate the values of xx and yy when the other variables are zero and join those points to get the graph.