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Question

Question: How do you graph \(y=\dfrac{5}{4}x+5\) ?...

How do you graph y=54x+5y=\dfrac{5}{4}x+5 ?

Explanation

Solution

The equation of y=mx+cy=mx+c is the equation of a straight line so the graph of y=mx+cy=mx+c is a straight line where m is the slope of line and c is the y intercept of line that means the straight line cuts the Y axis at (c,0)

Complete step by step answer:
The given equation in the question y=54x+5y=\dfrac{5}{4}x+5
We know that y=mx+cy=mx+c is a straight line where the slope is m and y=54x+5y=\dfrac{5}{4}x+5 is in the same format as y=mx+cy=mx+c so we can say y=54x+5y=\dfrac{5}{4}x+5 is a straight line so the graph of y=54x+5y=\dfrac{5}{4}x+5 will be a straight line
Here we can see 54\dfrac{5}{4} is in the place of m so the value of slope is 54\dfrac{5}{4} and the value of y intercept is 5 that means the straight line passes through (5,0)
We can draw the graph any straight line by using 2 point, 2 points is enough to draw the graph of straight line
First locate any 2 points on the Cartesian plane and join the 2 points to extend the line. That's it, the graph of straight is ready.
So let choose any 2 point we already know one point that is y intercept (5,0) let take another point (1,254)\left( 1,\dfrac{25}{4} \right)
Let’s locate above those points in Cartesian plane and join them

We can see C is the intercept and A is another point. We join the point and extend it . we got graph

Note:
The slope of the straight line y=mx+cy=mx+c is m which is constant at all points. But if the equation of line is given in ax+by+c=0ax+by+c=0 where b is not equal to 0 then we can write it y=abxcby=-\dfrac{a}{b}x-\dfrac{c}{b} , now we can see the slope of the line is ab-\dfrac{a}{b} and the y intercept is cb-\dfrac{c}{b} where b is not equal to 0.