Question

How do you graph $y=-\dfrac{4}{3}x+1$ using the slope and intercept?

Answer 1

At first, we compare the given equation with the slope-intercept form of a straight line and find out the slope and $y-\text{intercept}$ . Then we plot the point $\left( 0,1 \right)$ and draw another line through this point making an angle ${{\tan }^{-1}}\left( -\dfrac{4}{3} \right)$ with the $x-axis$ . This is the required line.

Complete step by step answer:
The given equation of the line is:
$y=-\dfrac{4}{3}x+1$
Comparing it with the general equation of a straight line in slope-intercept form $y=mx+c$ , where $m$ is the slope of the line and $c$ is the $y-\text{intercept}$ , we get
$m=-\dfrac{4}{3}$ and $c=1$
$y-\text{intercept}$ means that the point where the line intersects the $y-axis$ is $\left( 0,c \right)$ . As, in this problem, $c=1$ , the point where the given line cuts the $y-axis$ is $\left( 0,1 \right)$ . We therefore plot this point on the graph paper.
Slope of a line means the tangent of the angle that the line makes with the positive $x-axis$ . If we are given the slope of a line, then we can find out the angle that it makes with the $x-axis$ by the formula,
$\theta ={{\tan }^{-1}}m....formula1$
We now draw a line parallel to $x-axis$ through the point $\left( 0,1 \right)$ . The angle that the given line makes with the $x-axis$ is given by $formula1$ as

& \theta ={{\tan }^{-1}}\left( -\dfrac{4}{3} \right) \\\ & \Rightarrow \theta ={{126.87}^{\circ }} \\\ \end{aligned}$$ We draw another line making an angle $${{126.87}^{\circ }}$$ in clockwise direction with the parallel line that was previously drawn through the point $\left( 0,1 \right)$ . Therefore, we can conclude that the final line drawn at the specified angle passing through the point $\left( 0,1 \right)$ with the parallel line is nothing but the required line in the problem.  **Note:** The line parallel to $x-axis$ must be drawn at first to simplify the graph plot. The slope of the line being given, we must remember to find out the angle that the line must make with the $x-axis$ . Students often forget to find out the angle and mistakenly consider the slope to be the angle and end up with the wrong graph.