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Question

Question: How do you graph \[y = \dfrac{1}{2}{x^2}?\]...

How do you graph y=12x2?y = \dfrac{1}{2}{x^2}?

Explanation

Solution

The given question describes the operation of using arithmetic operations like addition/ subtraction/ multiplication/ division. Also, this problem involves substituting the xx in the given equation to find the value of yy. Because yy is the function of xx . By using the values of xxandyy we can easily draw the graph for the given equation.

Complete step by step solution:
The given equation is shown below,
y=12x2y = \dfrac{1}{2}{x^2}
We would draw the graph for the above equation.
As a first step,
We would assume xx value as given below,
x=.....2,1,0,1,2,....x = ..... - 2, - 1,0,1,2,....
By substituting the above-mentioned xx values in the given equation we can find the yy values.
The given equation is,
y = \dfrac{1}{2}{x^2}$$$$ \to \left( 1 \right)
Let’s substitute x=2x = - 2 in the equation(1)\left( 1 \right)we get,
y=12x2y = \dfrac{1}{2}{x^2}
y=12(2)2y = \dfrac{1}{2}{\left( { - 2} \right)^2}

y=12×4 y=2 y = \dfrac{1}{2} \times 4 \\\ y = 2 \\\

So, we get
When x=2x = - 2 the value ofyyis22.
Let’s substitutex=1x = - 1 in the equation(1)\left( 1 \right)we get,
y=12x2y = \dfrac{1}{2}{x^2}
y=12(1)2y = \dfrac{1}{2}{\left( { - 1} \right)^2}

y=12×1 y=12 y = \dfrac{1}{2} \times 1 \\\ y = \dfrac{1}{2} \\\

So we get,
When x=1x = - 1 the value ofyyis12\dfrac{1}{2}.
Let’s substitute x=0x = 0 in the equation (1)\left( 1 \right), we get
y=12x2y = \dfrac{1}{2}{x^2}
y=12(0)2y = \dfrac{1}{2}{\left( 0 \right)^2}
y=0y = 0
So we get,
When x=0x = 0 the value yy is equal to00.
Let’s substitute x=1x = 1 in the equation (1)\left( 1 \right), we get
y=12x2y = \dfrac{1}{2}{x^2}
y=12(1)2y = \dfrac{1}{2}{\left( 1 \right)^2}
y=12y = \dfrac{1}{2}
So we get,
When x=1x = 1 the value yyis equal to 12\dfrac{1}{2}.
Let’s substitute x=2x = 2 in the equation (1)\left( 1 \right) we get,
y=12x2y = \dfrac{1}{2}{x^2}
y=12(2)2y = \dfrac{1}{2}{\left( 2 \right)^2}

y=12×4 y=2 y = \dfrac{1}{2} \times 4 \\\ y = 2 \\\

So we get,
When x=2x = 2 the value ofyyis22.

xx2 - 21 - 1001122
yy2212\dfrac{1}{2}0012\dfrac{1}{2}22

Let’s make a tabular column by using the values of xx and yy.
By using this table we can easily draw the graph for the given equation.

The above graph represents the equation y=12x2y = \dfrac{1}{2}{x^2}.

Note: This question describes the operation of addition/ subtraction/ multiplication/ division. Note that when the given equation is in the form of y=ax2y = a{x^2} then the graph must be in parabolic shape.
Also, note that anything power zero will be one, and zero power anything will be one. When multiplying two different sign terms remember the following things,

  1. ()×()=(+)\left( - \right) \times \left( - \right) = \left( + \right)
  2. (+)×(+)=(+)\left( + \right) \times \left( + \right) = \left( + \right)
  3. ()×(+)=()\left( - \right) \times \left( + \right) = \left( - \right)