Solveeit Logo

Question

Question: How do you graph \(y=-\dfrac{1}{2}\cos x\) ?...

How do you graph y=12cosxy=-\dfrac{1}{2}\cos x ?

Explanation

Solution

To graph the given function y=12cosxy=-\dfrac{1}{2}\cos x, first of all, we are going to draw the graph of cosx\cos x and then multiply the negative of 1 with cosx\cos x. When we multiply the negative of 1 with cosx\cos x then we have to take the mirror image of the graph of cosx\cos x in the line mirror present on the x axis. Now, we will multiply one half to cosx-\cos x then we have to shrink the y value of the graph of cosx-\cos x by one half.

Complete step-by-step answer:
The function given in the above problem which we have to graph is as follows:
y=12cosxy=-\dfrac{1}{2}\cos x
To draw the above function on the graph paper, first of all, we are going to draw cosx\cos x on the graph. In the below, we have drawn the graph of cosx\cos x.

Now, we are going to draw the graph of cosx-\cos x by taking the mirror image of the above graph in the line mirror placed at x axis.

The dotted line in the above graph is the mirror image of cosx\cos x in the line mirror of x axis so the dotted line pink graph above is of cosx-\cos x.
Now, we are drawing the graph of 12cosx-\dfrac{1}{2}\cos x by shrinking all the y values of the above graph by 12\dfrac{1}{2}.

In the above graph, as you can see that the y value of the blue curve is lesser than that of the dotted pink curve so the blue curve is the graph of 12cosx-\dfrac{1}{2}\cos x.
Now, we are eliminating the pink dotted curve from the above graph then we get,

Hence, we have drawn the graph of y=12cosxy=-\dfrac{1}{2}\cos x which is shown below:

Note: The mistake that could be possible in the drawing of the above graph is that when converting graph from cosx\cos x to cosx-\cos x, you will take the mirror image of the graph in the line mirror placed on the y axis because you think that all the y values are changing so line mirror should present on the y axis. But this is the wrong way of conversion from cosx\cos x to cosx-\cos x so make sure you won’t make this mistake in the exam.