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Question

Question: How do you graph \(y = - \csc x\)...

How do you graph y=cscxy = - \csc x

Explanation

Solution

Graphing the negative of a function essentially implies flipping the function about the X-axis. This question can be approached similarly. We can start by drawing the graph of y=cscxy = \csc x and then try flipping it around the X-axis.

Complete Step by Step Solution:
We should start solving the question by drawing the graph of y=cscxy = \csc x.
The graph of y=cscxy = \csc x is as follows:

The range of the x-axis is set from 2π- 2\pi to 2π2\pi. An asymptote of a curve can be described as a line such that the distance between the curve and line approaches zero when either one or both of the x and y coordinates tend to infinity.
The graph of y=cscxy = \csc x has asymptotes at the point nπn\pi . n is an integer.
When x=π2±2nπx = \dfrac{\pi }{2} \pm 2n\pi , then the value of y=1y = 1
When x=3π2±2nπx = \dfrac{{3\pi }}{2} \pm 2n\pi , then the value of y=1y = - 1
The negative sign is used in order to change the sign of the y values. Thus, the positive values of y become negative and the negative values of y become positive. In this case, we’re essentially flipping the equation around the X-axis.
Thus, the graph of y=cscxy = - \csc x can be drawn as follows:

Note:

The cosecant of any angle, θ\theta in a right-angled triangle is defined as:
cscθ=length(hypotenuse)length(opposite)\csc \theta = \dfrac{{length\left( {hypotenuse} \right)}}{{length(opposite)}}
Cosecant of an angle can be related to the sine of the angle in the following manner:
cscθ=1sinθ\csc \theta = \dfrac{1}{{\sin \theta }}