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Question: How do you graph \(y=4\csc 2x\)?...

How do you graph y=4csc2xy=4\csc 2x?

Explanation

Solution

First compare the function y=4csc2xy=4\csc 2x with the base function. Find the period and frequency of the function. Then take some different ‘y’ values for corresponding ‘x’ values and plot the graph.

Complete step-by-step solution:
y=4csc2xy=4\csc 2x is a trigonometric function of the base function y=cscxy=\csc x.
As we know cscx\csc x is the reciprocal of sinx\sin x, so cscx\csc x will not be defined at the points where sinx\sin x is 0. Hence, the domain of cscx\csc x will be RnπR-n\pi , where ‘R’ is the set of real numbers and ‘n’ is an Integers. Similarly, the range of cosec x will be R(1,1)R-\left( -1,1 \right). Since, sinx\sin x lies between (1,1)\left( -1,1 \right), so cscx\csc x can never lie in the region of (1,1)\left( -1,1 \right).
Now, considering our equation y=4csc2xy=4\csc 2x
Here the range of the function will be 4 times from that of y=cscxy=\csc x
Again as we know the period of cscx=2π\csc x=2\pi , so the period of y=4csc2xy=4\csc 2x will be=2π2=π=\dfrac{2\pi }{\left| 2 \right|}=\pi
And the frequency=1π=\dfrac{1}{\pi } (as frequency is the reciprocal of time period)
For the graph we have to take some different values of ‘y’ for corresponding ‘x’ values

xπ4\dfrac{\pi }{4}3π4\dfrac{3\pi }{4}5π4\dfrac{5\pi }{4}7π4\dfrac{7\pi }{4}9π4\dfrac{9\pi }{4}
y44-444-44

Taking these values of ‘x’ and ‘y’ the graph can be drawn as

Note: The base function of y=4csc2xy=4\csc 2x is y=cscxy=\csc x. From the above graph, we can conclude that the graph of the function cscx\csc x does not have a maximum or a minimum value. The function goes to infinity periodically and is symmetric with the origin.