Question
Question: How do you graph \(y = 2\cos x\)?...
How do you graph y=2cosx?
Solution
In order to plot the given trigonometric function, we first find the time period. Then we see how many intervals there are going to be in that time period.
Since it’s a graph of cosine and as we know that cos0∘=1, therefore the graph of cosine should start from 1 but as we have our trigonometric function as y=2cosx, therefore all the values are multiplied by 2.
Thus our graph starts from 2 on the y-axis. Once we have our time period and time intervals, we can plot it on the x-axis and make our amplitude on the y-axis and get our required graph.
Complete step-by-step solution:
The given trigonometric function is: y=2cosx
In order to solve this, we first need to find the time period by using the formula: b2π , where in an expression y=2cosx, a=2 and coefficient of x=b. Here the coefficient of x=1
Therefore time period=12π=2π
Now we know that cos0∘=1 , therefore the graph should start from 1 on the y-axis but as the function is given as y=2cosx, therefore the values are multiplied with 2
We take suitable units distance and plot the time period on the x-axis in terms of π and plot the y-axis with usual numbers.
According to the graph that we have, the time period is till 2π , therefore there are four time intervals such as: 0,2π,π,23π,2π . We make our graph as shown below:
Note: The trigonometric functions are real functions which relate an angle of a right-angled triangle to the ratio of the other two sides. The trigonometric functions widely used are: sine, cosine and tangent and their reciprocals such as cosecant, secant and cot respectively.
If we plot the value of sine on a graph, then we will find that the values of sine are positive from 0 to π which corresponds to positive values of sine in the first and the second quadrant.
If we plot the value of cosine on a graph, then we will find that the values of cosine are positive from 0 to 2π and then negative from 2π to 23π corresponding to the first quadrant and the second and third quadrants respectively.