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Question: How do you graph \(y = 1 + \sin \left( {\dfrac{1}{2}x} \right)\)?...

How do you graph y=1+sin(12x)y = 1 + \sin \left( {\dfrac{1}{2}x} \right)?

Explanation

Solution

The given function is y=1+sin(12x)y = 1 + \sin \left( {\dfrac{1}{2}x} \right)
Use the form asin(bxc)+da\sin (bx - c) + d to find the variables used to find the amplitude, period, phase shift and vertical shift.
We find the xx point, put 0,π,2π,3π,4π0,\pi ,2\pi ,3\pi ,4\pi
Finally we get the result. And to draw a graph

Complete step-by-step solution:
The given function is y=1+sin(12x)y = 1 + \sin \left( {\dfrac{1}{2}x} \right)
We rewrite the function y=sin(12x)+1y = \sin \left( {\dfrac{1}{2}x} \right) + 1
Use the form asin(bxc)+da\sin (bx - c) + d to find the variables used to find the amplitude, period, phase shift and vertical shift.
a=0a = 0
b=12b = \dfrac{1}{2}
c=0c = 0
d=1d = 1
Find the amplitudea\left| a \right|
Amplitude: 11
Find the period using the formula2πb\dfrac{{2\pi }}{{\left| b \right|}}
The period of the function can be calculated using 2πb\dfrac{{2\pi }}{{\left| b \right|}}
Replace bb with 12\dfrac{1}{2} in the formula for period.
Period2π12\dfrac{{2\pi }}{{\left| {\dfrac{1}{2}} \right|}}
We solve the equation:
12\dfrac{1}{2} is approximately 0.50.5 which is positive so remove the absolute value
Period:2π12\dfrac{{2\pi }}{{\dfrac{1}{2}}}
Multiply the numerator by the reciprocal of the denominator, 2π×22\pi \times 2
Multiply 22 by2, 4π4\pi
Find the phase shift using the formula cb\dfrac{c}{b}.
Replace the values of cc and bb in the equation for phase shift.
012\Rightarrow \dfrac{0}{{\dfrac{1}{2}}}
Zero divide by anything the number is zero, hence we get
00
The vertical shift dd is 11
List the properties of the trigonometric function.
Amplitude: 11
Period: 4π4\pi
Phase shift: 00
Vertical shift: 11
Select a few points to graph.
Find the point at x=0x = 0
y=sin(12x)+1\Rightarrow y = \sin \left( {\dfrac{1}{2}x} \right) + 1
Replace the variable xx with the 00 in the expression
f(0)=sin(02)+1\Rightarrow f(0) = \sin \left( {\dfrac{0}{2}} \right) + 1
Divide 00 by 22, hence we get
f(0)=sin0+1\Rightarrow f(0) = \sin 0 + 1
Thesin0\sin 0 value is 00, hence we get
f(0)=0+1\Rightarrow f(0) = 0 + 1
The zero terms vanish
f(0)=1\Rightarrow f(0) = 1
Find the point at x=πx = \pi
f(π)=sin(π2)+1\Rightarrow f(\pi ) = \sin \left( {\dfrac{\pi }{2}} \right) + 1
Thesin(π2)\sin \left( {\dfrac{\pi }{2}} \right)value is11
f(π)=1+1\Rightarrow f(\pi ) = 1 + 1
Add11and11
f(π)=2\Rightarrow f(\pi ) = 2
Find the point at x=2πx = 2\pi
f(2π)=sin(2π2)+1\Rightarrow f(2\pi ) = \sin \left( {\dfrac{{2\pi }}{2}} \right) + 1
Cancel the common factor, hence we get
f(2π)=sin(π)+1\Rightarrow f(2\pi ) = \sin \left( \pi \right) + 1
Thesin(π)\sin \left( \pi \right) value is 00
f(2π)=0+1\Rightarrow f(2\pi ) = 0 + 1
Add 00 and11
f(2π)=1\Rightarrow f(2\pi ) = 1
Find the point at x=3πx = 3\pi
f(3π)=sin(3π2)+1\Rightarrow f(3\pi ) = \sin \left( {\dfrac{{3\pi }}{2}} \right) + 1
Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because sine is negative in the fourth quadrant.
Cancel the common factor, hence we get
f(3π)=sin(π2)+1\Rightarrow f(3\pi ) = - \sin \left( {\dfrac{\pi }{2}} \right) + 1
Thesin(π2)\sin \left( {\dfrac{\pi }{2}} \right)value is11
f(3π)=1×1+1\Rightarrow f(3\pi ) = - 1 \times 1 + 1
Multiply 1 - 1 by 11
f(3π)=1+1\Rightarrow f(3\pi ) = - 1 + 1
Subtract 1 - 1 by 11
f(3π)=0\Rightarrow f(3\pi ) = 0
Find the point at x=4πx = 4\pi
f(4π)=sin(4π2)+1\Rightarrow f(4\pi ) = \sin \left( {\dfrac{{4\pi }}{2}} \right) + 1
Cancel the common factor, hence we get
f(4π)=sin(2π)+1\Rightarrow f(4\pi ) = \sin \left( {2\pi } \right) + 1
Thesin(2π)\sin \left( {2\pi } \right)value is00
f(4π)=0+1\Rightarrow f(4\pi ) = 0 + 1
Add 00 and 11
f(4π)=1\Rightarrow f(4\pi ) = 1

xxf(x)f(x)
0011
π\pi 22
2π2\pi 11
3π3\pi 00
4π4\pi 11

Note: The sine and cosine functions are useful for one very important reason, since they repeat in a regular pattern. There are vast arrays of things in and around us that repeat periodically. For example, the rising and setting of the sun, the motion of a spring up and down, the tides of the ocean and so on, are repeating at regular intervals of time. All periodic behavior can be studied through combinations of the sine and cosine functions.
Periodic functions are used throughout science to describe oscillations, waves and other phenomena that occur periodically.