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Question: How do you graph \[x+3y=9\]?...

How do you graph x+3y=9x+3y=9?

Explanation

Solution

Here, in this problem, we have to graph the given equation. So, we have to find x-intercept and y-intercept with the given equation. We already know that for x-intercept the value of y is 0 and for y-intercept the value of x is 0, using this we can find the x and y coordinates and can plot the coordinate points in the graph.

Complete step by step answer:
We know that the given equation is,
x+3y=9x+3y=9……… (1)
Now we have to find x-coordinate.
We know that at x-intercept, y is equal to 0, substituting y = 0 in equation (1), we get

& \Rightarrow x+3\left( 0 \right)=9 \\\ & \Rightarrow x=9 \\\ \end{aligned}$$ Therefore, the x coordinate is $$\left( 9,0 \right)$$. Now we have to find the y-coordinate. We know that at y-intercept, the value of x is 0, substituting x = 0 in equation (1), we get $$\Rightarrow 0+3y=9$$ We can divide by 3 on both sides, we get $$\begin{aligned} & \Rightarrow \dfrac{3y}{3}=\dfrac{9}{3} \\\ & \Rightarrow y=3 \\\ \end{aligned}$$ Therefore, the y-coordinate is $$\left( 0,3 \right)$$. We can also find other two points to be plotted by assuming value to x and y. We can assume for y = 1, then the value of x from equation (1) is, $$\begin{aligned} & \Rightarrow x+3\left( 1 \right)=9 \\\ & \Rightarrow x=6 \\\ \end{aligned}$$ We can assume for y = 2, then the value of x from equation (1) is, $$\begin{aligned} & \Rightarrow x+3\left( 2 \right)=9 \\\ & \Rightarrow x=3 \\\ \end{aligned}$$ Therefore, the other two points are $$\left( 6,1 \right),\left( 3,2 \right)$$ Now we can plot the x-coordinate $$\left( 9,0 \right)$$, y-coordinate $$\left( 0,3 \right)$$ and other points $$\left( 6,1 \right),\left( 3,2 \right)$$ ![](https://www.vedantu.com/question-sets/0257c7e2-bfcb-40c7-a5ae-84b05330ec755034019036525889072.png) **Note:** Students make mistakes while finding x-intercept and y-intercept, we should always remember that, at x-intercept, the value of y is 0 and at y-intercept, the value of x is 0. We can assume any other points to find other points to be plotted in the graph.