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Question

Question: How do you graph \[x-2y=1\] using the intercepts?...

How do you graph x2y=1x-2y=1 using the intercepts?

Explanation

Solution

We can draw the graph using intercepts concept. First we have to find the xx and yy intercepts. we have to make xx as 00 while calculating y intercept and we have to make yy as 00 while calculating xx intercept. By solving this we can get the xx and yy intercepts to draw the graph.

Complete step by step answer:
Given equation is
x2y=1x-2y=1
Now we have to find the xx intercept of the equation.
To find it we have to substitute the yy value with 00.
By substituting it and simplifying it we will get the xx intercept .
Now we are going to substitute y=0y=0 in the equation.
We will get
x2(0)=1\Rightarrow x-2\left( 0 \right)=1
x0=1\Rightarrow x-0=1
From this we can write
x=1\Rightarrow x=1
So the xx intercept of the equation is 11
The point to plot on the graph is (1,0)\left( 1,0 \right)
Now we have to find the yy intercept of the equation.
To find it we have to substitute the xx value with 00.
By substituting it and simplifying it we will get the yy intercept .
Now we are going to substitute x=0x=0 in the equation.
We will get
02y=1\Rightarrow 0-2y=1
2y=1\Rightarrow -2y=1
We have to divide the equation with 22 on both sides
From this we can write
2y2=12\Rightarrow \dfrac{-2y}{2}=\dfrac{1}{2}
By simplifying it we will get
y=0.5\Rightarrow -y=0.5
To find the value of yy we have to multiply the equation with the- sign.
We will get
y=0.5\Rightarrow y=-0.5
So the yy intercept of the equation is 0.5-0.5
The point to plot on the graph is (0,0.5)\left( 0,-0.5 \right)
So the intercepts of xx and yy are 11 and 0.5-0.5 respectively.
Now we have to plot the graph it will look like

Note: We can also take different values for xx and yy and plot the graph. But here it is mentioned as an intercept we are taking the values as 00 otherwise we can take the values of our own choice and draw the graph.