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Question: How do you graph using slope and intercept of \[8x - 6y = - 20\] ?...

How do you graph using slope and intercept of 8x6y=208x - 6y = - 20 ?

Explanation

Solution

Hint : Here in this given equation is a linear equation. Here we have to plot a graph using slope and intercept, to this first solve for one variable. To solve this equation for y by using arithmetic operation we can shift the x variable to RHS then the resultant equation will be in the form of y=mx+by = mx + b later we can plot the graph for the resultant equation.

Complete step by step solution:
The given equation is a linear equation. These equations are defined for lines in the coordinate system. An equation for a straight line is called a linear equation. The general representation of the straight-line equation is y=mx+by = mx + b , it involves only a constant term and a first-order (linear) term, where m is the slope and b is the y-intercept. Occasionally, this equation is called a "linear equation of two variables," where y and x are the variables.
Consider the given equation
8x6y=20\Rightarrow 8x - 6y = - 20
Rearrange the equation because we have to shift the variable x and its coefficient to the RHS so subtract 8x on both side, then
8x6y8x=208x\Rightarrow 8x - 6y - 8x = - 20 - 8x
On simplification, we get
6y=(8x+20)\Rightarrow - 6y = - \left( {8x + 20} \right)
Cancel ' - ' ve sign on both side, then
6y=8x+20\Rightarrow 6y = 8x + 20
Divide both side by 6
66y=86x+206\Rightarrow \dfrac{6}{6}y = \dfrac{8}{6}x + \dfrac{{20}}{6}
On simplification, we get
y=43x+103\Rightarrow y = \dfrac{4}{3}x + \dfrac{{10}}{3}
Comparing the above equation with the straight-line equation is y=mx+by = mx + b .
Slope: m=43m = \dfrac{4}{3} and
y- intercept: (0,103)\left( {0,\dfrac{{10}}{3}} \right)
the graph of the equation y=43x+103y = \dfrac{4}{3}x + \dfrac{{10}}{3} using slope and intercept is given by:
when x=0x = 0 then y=103y = \dfrac{{10}}{3}
therefore, (x,y)=(0,103)=(0,3.33)\left( {x,y} \right) = \left( {0,\dfrac{{10}}{3}} \right) = \left( {0,3.33} \right)
when, y=0y = 0 then x=103×34x=52x = - \dfrac{{10}}{3} \times \dfrac{3}{4} \Rightarrow x = - \dfrac{5}{2}
therefore, (x,y)=(52,0)=(2.5,0)\left( {x,y} \right) = \left( { - \dfrac{5}{2},0} \right) = \left( { - 2.5,0} \right)

Note : The algebraic equation or an expression is a combination of variables and constants, it also contains the coefficient. The alphabets are known as variables. The x, y, z etc., are called as variables. The numerals are known as constants. The numeral of a variable is known as co-efficient. We have 3 types of algebraic expressions namely monomial expression, binomial expression and polynomial expression. By using the tables of multiplication, we can solve the equation.