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Question

Question: How do you graph the inequality \[x + y < 3\] ?...

How do you graph the inequality x+y<3x + y < 3 ?

Explanation

Solution

First we need to draw the graph of the equation x+y=3x + y = 3. We use intercept form to draw the graph. That is we find the coordinate of the given equation lying on the line of x- axis, we can find this by substituting the value of ‘y’ is equal to zero (x-intercept). Similarly we can find the coordinate of the equation lying on the line of y- axis, we can find this by substituting the value of ‘x’ equal to zero (y-intercept). After drawing the graph we can check in which region the inequality satisfies.

Complete step by step answer:
Given, x+y<3x + y < 3. Now consider x+y=3x + y = 3,
To find the x-intercept. That is the value of ‘x’ aty=0y = 0. Substituting this in the given equation. We have,
x+0=3x + 0 = 3
x=3\Rightarrow x = 3
Thus we have a coordinate of the equation which lies on the line of x-axis. The coordinate is (3,0)(3,0). To find the y-intercept. That is the value of ‘y’ at x=0x = 0. Substituting this in the given equation we have,
0+y=30 + y = 3
y=3\Rightarrow y = 3
Thus we have a coordinate of the equation which lies on the line of the y-axis. The coordinate is (0,3)(0,3). Thus we have the coordinates (3,0)(3,0) and (0,3)(0,3). Let’s plot a graph for these coordinates.We take scale x-axis= 1 unit = 1 units and y-axis= 1 unit = 1 units.

We expanded the point touching the intercepts. We took a coordinate above and below the equation of line (see in above graph).
That is (x,y)=(2,2)(x,y) = (2,2) and now put it in the inequality,
2+2<32 + 2 < 3
4<3\Rightarrow 4 < 3. Which is wrong.
Now take a coordinate below the equation of line,
That is (x,y)=(1,1)(x,y) = (1,1)
1+1<31 + 1 < 3
2<3\Rightarrow 2 < 3. Which is true.
In the above graph the shaded region is the solution of the given inequality.

Note: If we take any coordinate point below the line of the graph, the inequality satisfies. Also if we take a point on the line, the inequality won’t be satisfied. A graph shows the relation between two variable quantities, it contains two axes perpendicular to each other namely the x-axis and the y-axis. Each variable is measured along one of the axes. In the question, we are given one linear equation containing two variables namely x and y, x is measured along the x-axis and y is measured along the y-axis while tracing the given equations.