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Question: How do you graph line through the point \[\left( {5, - 3} \right)\] with undefined slope?...

How do you graph line through the point (5,3)\left( {5, - 3} \right) with undefined slope?

Explanation

Solution

If the slope of a line is undefined, then the line is a vertical line, so it cannot be written in slope-intercept form, but it can be written in the form: x=ax = a, where a is a constant. Here, the line has an undefined slope and passes through the point (5,3)\left( {5, - 3} \right), then the equation of the line is at x=5x = 5.

Complete step by step solution:
The line with undefined slope means that the line is parallel to the y-axis (If we measure its slope, then you would get division by zero which is undefined)
The equation of the line is x=ax = a, where a is the value of the x-coordinates that the line passes through.
In this case it passes through(5,3)\left( {5, - 3} \right)hencex=5x = 5 is the equation.
To graph plot (5,3)\left( {5, - 3} \right), (5,1)\left( {5,1} \right) and so on any point with x=5x = 5.
Here is the graph of x=5x = 5.

As shown above, the graph line through the point (5,3)\left( {5, - 3} \right), is a vertical line as the slope of the line is undefined.

Note: The key point to note is that, if the slope of the line is undefined, then, by definition the line is a vertical line. Since we did not have a change in the x values, the denominator of our slope is 0. This means that we have an undefined slope. The slope of a line characterizes the direction of a line and to find the slope, you divide the difference of the y-coordinates of two points on a line by the difference of the x-coordinates of those same two points.