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Question

Question: How do you graph \(f(x) = 1 - \cos 3x\)?...

How do you graph f(x)=1cos3xf(x) = 1 - \cos 3x?

Explanation

Solution

This problem deals with finding the graph of the given function. The function involves a trigonometric function which is a cosine trigonometric function. The general equation or a general function of a cosine function is denoted by Acos(B(xC))+DA\cos \left( {B\left( {x - C} \right)} \right) + D. Where this particular function has a period, amplitude and phase shift. The period of a periodic function is the interval between two matching points on the graph. The period of cosine function is 2π2\pi .

Complete step-by-step answer:
Any function is denoted in such a way, where f(x)=Acos(B(xC))+Df(x) = A\cos \left( {B\left( {x - C} \right)} \right) + D
f(x)=Acos(B(xC))+D\Rightarrow f(x) = A\cos \left( {B\left( {x - C} \right)} \right) + D
Here AA is the amplitude of the function, PP is the period of the function, CC is the phase shift and DD is the vertical shift of the given function.
P=2πB\Rightarrow P = \dfrac{{2\pi }}{B}
Here on comparing the given function f(x)=1cos3xf(x) = 1 - \cos 3x with the standard form of cosine function which is f(x)=Acos(B(xC))+Df(x) = A\cos \left( {B\left( {x - C} \right)} \right) + D
f(x)=1cos3x\Rightarrow f(x) = 1 - \cos 3x
Here there are two things to be observed which are the amplitude of the function is -1 and the vertical shift is 1. As the amplitude is negative, the graph will be on the side of the negative vertical axis.
Here the period is by P=2πBP = \dfrac{{2\pi }}{B}, as given below, here BB is 3.
P=2π3\Rightarrow P = \dfrac{{2\pi }}{3}
There is no phase shift. So the graph of f(x)=1cos3xf(x) = 1 - \cos 3x, is given below:

Final Answer: The amplitude, period, phase shift and vertical shift for f(x)=1cos3xf(x) = 1 - \cos 3x are -1, 2π3\dfrac{{2\pi }}{3} , 0 and 1 respectively.

Note:
Please note that the fundamental period of a function is the period of the function which are of the form, f(x+k)=f(x)f\left( {x + k} \right) = f\left( x \right) and f(x)=f(x+k)f\left( x \right) = f\left( {x + k} \right), then kk is called the period of the function and the function ff is called a periodic function. In other words, it is the distance along the x-axis that the function has to travel before it starts to repeat its pattern. The basic sine and cosine functions have a period of 2π2\pi , while tangent has a period of π\pi .