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Question

Question: How do you graph \(-4x+y=2\)?...

How do you graph 4x+y=2-4x+y=2?

Explanation

Solution

To draw the graph of the given equation 4x+y=2-4x+y=2. First of all, we are going to put xx equal to 0 in this equation and then will see the value of y we are getting. Then we will plot this point where x is 0 and the y corresponding to this x graphically. After that we are going to put yy equal to 0 in the above equation and see the values of xx we are getting and then plot these x and y coordinates on the graph. Now, we will join these two points to get the straight line.

Complete answer:
The equation of a straight line which we are given is as follows:
4x+y=2-4x+y=2
Now, we are going to substitute the value of xx equal to 0 in the above equation.
4(0)+y=2 y=2 \begin{aligned} & -4\left( 0 \right)+y=2 \\\ & \Rightarrow y=2 \\\ \end{aligned}
From the above, we got the point (0,2)\left( 0,2 \right). Now, we are going to plot this point on the graph paper.

Now, we are going to substitute y equal to 0 in the above equation.
4x+0=2 4x=2 \begin{aligned} & -4x+0=2 \\\ & \Rightarrow -4x=2 \\\ \end{aligned}
Dividing -4 on both the sides we get,
x=24=12x=-\dfrac{2}{4}=-\dfrac{1}{2}
From the above, the x and y coordinates of the second point are (12,0)\left( -\dfrac{1}{2},0 \right) . Let us draw this point (12,0)\left( -\dfrac{1}{2},0 \right) on the graph paper and we get,

Now, to draw the equation of a straight line we are going to join these two points A and B and we will get,

Hence, we have graphically drawn the given equation of a straight line.

Note: We can check the straight line that we drew is correct or not by taking a point on the straight line whose x coordinate is -1 and then to know the y coordinate of that point we are going to draw a perpendicular from this point on to the y axis. The foot of the perpendicular is the coordinate of y axis of that point.

In the above figure, the dotted line segment DE is the perpendicular drawn from point D to y axis and the foot of the perpendicular is -2. Hence, the y coordinate of that point D on the straight line is -2.
Now, we can check whether the y coordinate of point D is -2 or not. Let us substitute the x coordinate as -1 in the above equation we get,
4(1)+y=2 4+y=2 y=2 \begin{aligned} & -4\left( -1 \right)+y=2 \\\ & \Rightarrow 4+y=2 \\\ & \Rightarrow y=-2 \\\ \end{aligned}
From the above, we have got the same value of y which we got from the graph. Hence, the graph that we drew corresponding to the given equation is correct.