Solveeit Logo

Question

Question: How do you find the \(z\)- score for which \(80\%\) of the distribution’s area lies between \(-z\) a...

How do you find the zz- score for which 80%80\% of the distribution’s area lies between z-z and zz?

Explanation

Solution

In this question we have to find the zz- score for 80%80\% of the distribution therefore we will first calculate the value of α\alpha which will be the unwanted area and since we are working on the normal distribution which is symmetric on both sides, we will only take the value of α\alpha on one side of the graph and then use the zz- score table to get the zz- score for the given value of α\alpha .

Complete step by step solution:
We have to find the zz- score for which 80%80\% of the distribution’s area lies between z-z and zz.
Therefore, first we have to find the alpha of the region we don’t want. Since we have to find the zz- score for 80%80\% of the area, the unused area can be calculated as:
α=100%80%\Rightarrow \alpha =100\%-80\%
Now on expanding the percentages and writing it as a fraction, we get:
α=10010080100\Rightarrow \alpha =\dfrac{100}{100}-\dfrac{80}{100}
Now on taking the lowest common multiple of both the fractions, we get:
α=10080100\Rightarrow \alpha =\dfrac{100-80}{100}
Which can be simplified as:
α=20100\Rightarrow \alpha =\dfrac{20}{100}
On simplifying the fraction, we get:
α=0.2\Rightarrow \alpha =0.2
Now this value of α\alpha represents both sides of the standard normal distribution. And since the distribution is symmetric, we can divide the value of α\alpha by 22.
On dividing α\alpha by 22, we get:
α2=0.22\Rightarrow \dfrac{\alpha }{2}=\dfrac{0.2}{2}
On simplifying, we get:
α2=0.1\Rightarrow \dfrac{\alpha }{2}=0.1
Now we will use the zz- score table to get the zz- score for the given value of α/2\alpha /2.
Now from the zz- score table we can see that for the value 0.10.1, the value of zz is 1.28-1.28, which is the negative zz value therefore the positive zz value will be 1.281.28 which is the required range.

Therefore, the zz- score for 80%80\% of the distribution’s area lies between 1.28-1.28 and 1.281.28.

Note: It is to be remembered that the zz score table is used in the normal distribution to find the probability. The probability of any event can never be negative of greater than one.
There also exist other types of probability distributions such as the binomial distribution, Bernoulli distribution etc.