Question
Question: How do you find the x-intercept and y-intercept of \(4y = 16\) ?...
How do you find the x-intercept and y-intercept of 4y=16 ?
Solution
We have given an equation of a line as 4y=16 , which is a straight-line equation. A straight-line equation is always linear and represented as y=mx+c where mis the slope of the line and c is the y-intercept and m−c is the x-intercept .
Complete step-by-step solution:
We have equation of line,
4y=16
Divide by 4 both the side ,
y=4
We can write it as ,
y=0×x+4
Now we compare this given equation with the general linear equation i.e., y=mx+c
Hence ,
-Slope of the given line, m=0 .
-y-intercept of the given line , c=4 .
Therefore, we can say that point (0,4) lie on the line.
x-intercept of the given line , m−c=0−4 . (not define)
There is no x-intercept .
Additional Information: Slope of a line can also be found if two points on the line are given . let the two points on the line be (x1,y1),(x2,y2) respectively.
Then the slope is given by , m=x2−x1y2−y1 .
Slope is also defined as the ratio of change in y over the change in xbetween any two points.
y-intercept can also be found by substituting x=0.
Similarly, x-intercept can also be found by substituting y=0 .
Note: This type of linear equations sometimes called slope-intercept form because we can easily find the slope and the intercept of the corresponding lines. This also allows us to graph it.
We can quickly tell the slope i.e., m the y-intercepts i.e., (y,0) and the x-intercept i.e., (0,y) .we can graph the corresponding line .