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Question: How do you find the x and y intercepts for \( 4x + 5y = 20 \)...

How do you find the x and y intercepts for 4x+5y=204x + 5y = 20

Explanation

Solution

Hint : An intercept is the distance between the point where the curve crosses the x or y axis and the origin. If the curve passes through the x axis, then the distance between the origin and the intersection point on the x axis is called x intercept and similarly for y intercept.

Complete step-by-step answer :
Given to us is an equation of a curve 4x+5y=204x + 5y = 20
This curve cuts the x axis and y axis at a point each. When this curve meets the x axis, the value of y coordinate will be zero at that particular intersection point. So the coordinates of the x intercept would be (X,0)\left( {X,0} \right)
This point lies on the curve so it must satisfy the curve equation. Hence let us now substitute this point in the given curve equation.
4X+5(0)=204X + 5\left( 0 \right) = 20
On solving, we get X=204=5X = \dfrac{{20}}{4} = 5
Hence the x intercept is 55
Similarly, when the curve meets the y axis, the value of x coordinate will be zero at that intersection point and hence we can write the coordinates of the y intercept as (0,Y)\left( {0,Y} \right)
This point lies on the curve so we can substitute this point in the given equation to get 4(0)+5Y=204\left( 0 \right) + 5Y = 20
On solving, we get Y=205=4Y = \dfrac{{20}}{5} = 4
Therefore, the y intercept is 44
So, the correct answer is “4”.

Note : It is to be noted that we can also write the intercept points for both x and y axis. The intercept point for x axis would be (5,0)\left( {5,0} \right) since the x intercept is 55 and similarly the intercept point for y axis would be (0,4)\left( {0,4} \right) since the y intercept is 44