Question
Question: How do you find the \(x\) and \(y\) intercepts for \(3x - 4y = 12\)?...
How do you find the x and y intercepts for 3x−4y=12?
Solution
In this problem, we have given an equation and here we are asked to find the x and y intercept of the given equation and geometrically to solve this problem we need to substitute some value for x to find the x intercept and also substitute one value for y to find the y intercept.
Complete step-by-step answer:
The given equation is 3x−4y=12.
There are two axes in the graph. In that, the x-intercept is the value of x when the value of y is equal to zero.
This implies that when we substitute the value of y is equal to zero the given equation becomes,
⇒3x−4(0)=12
Multiplication of any number with zero is again zero. So the above equation becomes,
⇒3x−0=12
Simplify the terms,
⇒3x=12
Divide both sides by 3,
⇒x=4
So, the x-intercept is 4.
Now, the y-intercept is the value of y when the value of x is equal to zero.
This implies that when we substitute the value of x is equal to zero the given equation becomes,
⇒3(0)−4y=12
Simplify the terms,
⇒−4y=12
Divide both sides by -4,
⇒y=−3
So, the y-intercept is -3.
Hence, the x-intercept is 4 and the y-intercept is -3.
Note:
The intercepts of a graph are points at which the graph crosses the axes. The x-intercept is the point at which the graph crosses the x-axis. At this point, the y-coordinate is zero. The y-intercept is the point at which the graph crosses the y-axis. At this point, the x-coordinate is zero.
It is to be noted that we can also write the intercept points for both the x and y-axis. The intercept point for the x-axis would be (4,0) since the x-intercept is 4 and similarly the intercept point for the y-axis would be (0,-3) since the y-intercept is -3.