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Question: How do you find the x and y-intercept of \[5x + 3y = 30\]?...

How do you find the x and y-intercept of 5x+3y=305x + 3y = 30?

Explanation

Solution

If a point crosses the x-axis, then it is called x-intercept. If a point crosses the y-axis, then it is called y-intercept. To find the x and y-intercept of the given equation, for y-intercept we need to substitute xx= 0 in the given equation and solve for y, and for x-intercept substitute y = 0 in the given equation and solve for x.

Complete step-by-step solution:
The given equation is
5x+3y=305x + 3y = 30
To find the x-intercept, substitute y = 0 in the given equation and solve for x i.e.,
5x+3(0)=305x + 3\left( 0 \right) = 30
After simplifying we get
5x=305x = 30
Divide both sides by 5 to get the value of x as
5x5=305\dfrac{{5x}}{5} = \dfrac{{30}}{5}
x=305x = \dfrac{{30}}{5}
Therefore, the value of x is
x=6x = 6
Hence, the x-intercept of 5x+3y=305x + 3y = 30 is (6,0)\left( {6,0} \right).
To find the y-intercept, substitute xx= 0 in the given equation and solve for y i.e.,
5x+3y=305x + 3y = 30
5(0)+3y=305\left( 0 \right) + 3y = 30
After simplifying we get
3y=303y = 30
Divide both sides by 3 to get the value of y as
3y3=303\dfrac{{3y}}{3} = \dfrac{{30}}{3}
y=303y = \dfrac{{30}}{3}
Therefore, the value of y is
y=10y = 10
Hence, the y-intercept of 5x+3y=305x + 3y = 30 is (0,10)\left( {0,10} \right).
Therefore, the x and y-intercept of 5x+3y=305x + 3y = 30 is
(6,0)\left( {6,0} \right)and (0,10)\left( {0,10} \right).

Additional information:
The point where the line or curve crosses the axis of the graph is called intercept. If a point crosses the x-axis, then it is called x-intercept. If a point crosses the y-axis, then it is called y-intercept. If the axis is not specified, usually the y-axis is considered. It is y-coordinate of a point where a straight line or a curve intersects the y-axis.

Note: As per the given equation consists of x and y terms based on the intercept asked, we need to solve for it. For ex if y-intercept is asked substitute x=0 and solve for y and if x-intercept is asked substitute y=0 and solve for x and the y-intercept of an equation is a point where the graph of the equation intersects the y-axis.