Question
Question: How do you find the volume of the solid bounded by the coordinate planes and the plane \(3x + 2y + z...
How do you find the volume of the solid bounded by the coordinate planes and the plane 3x+2y+z=6?
Solution
Here, we are given the solid bounded by the coordinate planes and the plane 3x+2y+z=6 which is a tetrahedron. First, we will find the vertices of this tetrahedron. After that will use the formula of the volume of the tetrahedron by using its vertices to get our answer.
Complete step by step answer:
We are given the plane 3x+2y+z=6.
Let us now find the vertices of the solid.
First, we will find the vertex in x direction.
To find the vertex in the x direction, we will put y=0 and z=0.
3x+2y+z=6 ⇒3x=6 ⇒x=2
Therefore, vertex a=⟨2,0,0⟩.
Now, we will find the vertex in y direction.
To find the vertex in the y direction, we will put x=0 and z=0.
3x+2y+z=6 ⇒2y=6 ⇒y=3
Therefore, vertex b=⟨0,3,0⟩.
Now, we will find the vertex in z direction.
To find the vertex in the z direction, we will put x=0 and y=0.
3x+2y+z=6 ⇒z=6
Therefore, vertex c=⟨0,0,6⟩.
We know that the formula for finding the volume using the vertices of the tetrahedron is given by:
V=61a⋅(b×c)
We will now put the values of each of the vertices a=⟨2,0,0⟩, b=⟨0,3,0⟩ and c=⟨0,0,6⟩.