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Question

Question: How do you find the values of \[\theta \] given \[\tan \theta = 1\]?...

How do you find the values of θ\theta given tanθ=1\tan \theta = 1?

Explanation

Solution

The question is involving the trigonometric function. The tangent is one of the trigonometry ratios. Here in this question, by taking inverse tangent function on both sides of a given function then using the specified angle of trigonometric ratios we can get the required value of angle θ\theta .

Complete step by step explanation:
Tangent or tan is the one of the trigonometric function defined as the ratio between the opposite
side and adjacent side of right angled triangle with the angle θ\theta

The value of specified angles of the tan function is
tan0=0\tan {0^ \circ } = 0
tan30=32\tan {30^ \circ } = \dfrac{{\sqrt 3 }}{2}
tan45=1\tan {45^ \circ } = 1
tan60=3\tan {60^ \circ } = \sqrt 3
tan90=\tan {90^ \circ } = \infty

Now, Consider the given equation
tanθ=1\Rightarrow \,\,\,\tan \theta = 1

Take inverse function of tan i.e., tan1{\tan ^{ - 1}} on both side, then
tan1(tanθ)=tan1(1)\Rightarrow \,\,{\tan ^{ - 1}}\left( {\,\tan \theta } \right) = {\tan ^{ - 1}}\left( 1 \right)

As we now the x.x1=1x.{x^{ - 1}} = 1 , then
1.θ=tan1(1)\Rightarrow \,\,1.\theta = {\tan ^{ - 1}}\left( 1 \right)
θ=tan1(1)\Rightarrow \,\,\theta = {\tan ^{ - 1}}\left( 1 \right)

By the value specified angle
θ=45\Rightarrow \,\,\theta = {45^ \circ }

Now we convert angleθ\theta degree to radian by multiplying π180\dfrac{\pi }{{180}}, then
θ=45×π180\Rightarrow \,\,\theta = 45 \times \dfrac{\pi }{{180}}
θ=π4c\therefore \,\,\,\,\,\theta = {\dfrac{\pi }{4}^c}

However, the tangent function is positive in the first and third quadrants. To find the
second solution, add the reference angle from π\pi to find the solution in the fourth quadrant.
θ=π+π4\Rightarrow \,\,\theta = \pi + \dfrac{\pi }{4}
By taking 4 has LCM in RHS
θ=4π+π4\Rightarrow \,\,\theta = \dfrac{{4\pi + \pi }}{4}
θ=5π4c\therefore \,\,\,\,\,\theta = {\dfrac{{5\pi }}{4}^c}

The period of the tan(θ)\tan (\theta ) function is π\pi so value 1 will repeat every π\pi radians in
both directions.
θ=π4+nπ,5π4+nπ\Rightarrow \,\,\,\,\theta = \dfrac{\pi }{4} + n\pi ,\,\,\,\dfrac{{5\pi }}{4} + n\pi, for any
integernn

In general ,
θ=π4+nπ\therefore \,\,\,\,\theta = \dfrac{\pi }{4} + n\pi , for any integer nn

Hence, the values of θ\theta giventanθ=1\tan \theta = 1 is θ=π4+nπ\theta = \dfrac{\pi }{4} + n\pi , for any integer nn

Note: The trigonometry and inverse trigonometry is inverse of each other. To solve this kind of problem we need trigonometry and inverse trigonometry concepts. To find the value of θ\theta We use the inverse trigonometry concept. We have a table for trigonometry ratios for standard angles, using this we determine the value of θ\theta . And we can also verify the answer by substituting the value.