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Question

Question: How do you find the value of the expression \[\arccos \left( { - 0.7} \right)\]?...

How do you find the value of the expression arccos(0.7)\arccos \left( { - 0.7} \right)?

Explanation

Solution

In the above question, is based on the inverse trigonometry concept. The trigonometric functions are the relationship between the angles and the sides of the triangle. Since measure is given in the function, we need to find the angle of that particular measure of trigonometric function.

Complete step-by-step solution:
Given expression: arccos(0.7)\arccos \left( { - 0.7} \right)
arccos\arccos is an inverse trigonometric function which can also be written as cos1{\cos ^{ - 1}}. 1 - 1 here is just the way of showing that it is inverse of cosx\cos x. Inverse cosine does the opposite of cosine. Cosine function gives the angle which is calculated by dividing the adjacent side and hypotenuse in a right-angle triangle, but the inverse of it gives the measure of an angle.
The cosine of angle θ\theta is:
cosθ=AdjacentHypotenuse\cos \theta = \dfrac{{Adjacent}}{{Hypotenuse}}
Therefore, inverse of cosine is:
cos1(AdjacentHypotenuse)=θ{\cos ^{ - 1}}\left( {\dfrac{{Adjacent}}{{Hypotenuse}}} \right) = \theta
In the above cosine function, we have to find inverse of cosine function with given value 0.7 - 0.7
arccos(0.7)=134\arccos \left( { - 0.7} \right) = {134^ \circ }
Let x=arccos(0.7)x = \arccos \left( { - 0.7} \right)
We have to find all possible values of xx satisfying the equation x=arccos(0.7)x = \arccos \left( { - 0.7} \right).
So, take cos\cos on both sides of the equation to extract xx from inside the cos\cos .
cosx=0.7\cos x = - 0.7
Now, we will find the values of xx satisfying cosx=0.7\cos x = - 0.7…(i)
So, using the property cos(πx)=cosx\cos \left( {\pi - x} \right) = - \cos x and cos(0.7)=0.7953988302\cos \left( {0.7} \right) = 0.7953988302 in equation (i).
cosx=cos(0.795)\Rightarrow \cos x = - \cos \left( {0.795} \right)
cosx=cos(3.140.795)\Rightarrow \cos x = \cos \left( {3.14 - 0.795} \right)
x=2.345\Rightarrow x = 2.345
Now, using the property cos(π+x)=cosx\cos \left( {\pi + x} \right) = - \cos x and cos(0.7)=0.7953988302\cos \left( {0.7} \right) = 0.7953988302 in equation (i).
cosx=cos(0.795)\Rightarrow \cos x = - \cos \left( {0.795} \right)
cosx=cos(3.14+0.795)\Rightarrow \cos x = \cos \left( {3.14 + 0.795} \right)
x=3.935\Rightarrow x = 3.935
Since, the period of the cos(x)\cos \left( x \right) function is 2π2\pi so values will repeat every 2π2\pi radians in both directions.
x=2.345+2nπ,3.935+2nπx = 2.345 + 2n\pi ,3.935 + 2n\pi , for any integer nn.
Hence, the value of the expression arccos(0.7)\arccos \left( { - 0.7} \right) is 134134 degrees and 2.3452.345 radians.

Note: An important thing to note is that since the value is a negative value the cosine function is positive in the fourth quadrant so it is easy to predict then angle will be between 0 to 360 degree. If you need to find out the value in the first quadrant, we can subtract π\pi by 3.14 since the period of cosine is 2π2\pi .