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Question

Question: How do you find the value of \({\tan ^{ - 1}}\left( {\dfrac{4}{3}} \right)\) ?...

How do you find the value of tan1(43){\tan ^{ - 1}}\left( {\dfrac{4}{3}} \right) ?

Explanation

Solution

In this question we are asked to find the value of tan1(43){\tan ^{ - 1}}\left( {\dfrac{4}{3}} \right). This question can be solved by using the formula tan1(43)=y{\tan ^{ - 1}}\left( {\dfrac{4}{3}} \right) = y.

Complete step by step answer:
We are asked to find the value of tan1(43){\tan ^{ - 1}}\left( {\dfrac{4}{3}} \right)
Say this function is equal to y.
y=tan1(43)\Rightarrow y = {\tan ^{ - 1}}\left( {\dfrac{4}{3}} \right)
The best method to solve this question is by following the integral by numerical methods to get tan1(43){\tan ^{ - 1}}\left( {\dfrac{4}{3}} \right)
tan1(43)=04/311+x2dx\Rightarrow {\tan ^{ - 1}}\left( {\dfrac{4}{3}} \right) = \int_0^{4/3} {\dfrac{1}{{1 + {x^2}}}dx}
Which is approximately equal to 52.5 degrees.

Note: Trick to remember-
tanx=34\tan x = \dfrac{3}{4} here the numerator is equal to 33 and angle is equal to 37{37^ \circ }
tanx=43\tan x = \dfrac{4}{3}here the numerator is equal to 44 and angle is equal to 57{57^ \circ }
This is only valid for above angle in terms of tanx\tan x