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Question: How do you find the value of \[\csc ,\sec \], and \[\cot \] of theta in a unit circle?...

How do you find the value of csc,sec\csc ,\sec , and cot\cot of theta in a unit circle?

Explanation

Solution

Here we will first draw a circle with radius 1. Then by taking any one of the quadrants we will form a triangle in it. Finally, by using the basic formula of trigonometric angles we get the required value of the trigonometric functions.

Complete step-by-step answer:
First, as the radius of the circle is given 1 unit, we will draw a circle with radius one as,

Next, as we have to find the value of trigonometric identities we will form a triangle ABC inside the circle as,

As ABAB andBCBCare the radii of the circle their value is 1.
Using Pythagoras theorem, we get
AC2=AB2+BC2A{C^2} = A{B^2} + B{C^2}
Substituting AB=1AB = 1 and BC=1BC = 1 in the above equation, we get
AC2=12+12 AC2=1+1\begin{array}{l} \Rightarrow A{C^2} = {1^2} + {1^2}\\\ \Rightarrow A{C^2} = 1 + 1\end{array}
Adding the terms, we get
AC=2\Rightarrow AC = \sqrt 2
So, we get our diagram as,

Next, we know
1. sinθ=\sin \theta = Perpendicular ÷\div Hypotenuse
sinθ=ABAC=12\Rightarrow \sin \theta = \dfrac{{AB}}{{AC}} = \dfrac{1}{{\sqrt 2 }}
We know that cscθ=1sinθ\csc \theta = \dfrac{1}{{\sin \theta }}.
cscθ=112=2\csc \theta = \dfrac{1}{{\dfrac{1}{{\sqrt 2 }}}} = \sqrt 2
2. cosθ=\cos \theta = Base ÷\div Hypotenuse
cosθ=BCAC=12\Rightarrow \cos \theta = \dfrac{{BC}}{{AC}} = \dfrac{1}{{\sqrt 2 }}
We know that secθ=1cosθ\sec \theta = \dfrac{1}{{\cos \theta }}.
secθ=112=2\sec \theta = \dfrac{1}{{\dfrac{1}{{\sqrt 2 }}}} = \sqrt 2
3. cotθ=cosθsinθ\cot \theta = \dfrac{{\cos \theta }}{{\sin \theta }}
Substituting sinθ=12\sin \theta = \dfrac{1}{{\sqrt 2 }} and cosθ=12\cos \theta = \dfrac{1}{{\sqrt 2 }} in the above equation, we get
cotθ=1212=22=1\cot \theta = \dfrac{{\dfrac{1}{{\sqrt 2 }}}}{{\dfrac{1}{{\sqrt 2 }}}} = \dfrac{{\sqrt 2 }}{{\sqrt 2 }} = 1

Therefore, we get the value of cscθ,secθ\csc \theta ,\sec \theta and cotθ\cot \theta in a unit circle as 2,2\sqrt 2 ,\sqrt 2 and 1 respectively.

Note:
Trigonometry is a branch of mathematics that deals with specific functions of angles and also their application in calculations and simplification. The commonly used six types of trigonometry functions are defined as sine, cosine, tangent, cotangent, secant, and cosecant. Identities are those equations that are true for every variable. Reciprocal identities are used to cover the base of inverse values where cosecant is reciprocal of sine, secant is reciprocal of cosine and cotangent is reciprocal of a tangent.