Question
Question: How do you find the value of \[\csc ( - 210)?\]...
How do you find the value of csc(−210)?
Solution
We know that cosec(−x)=−cosecx .
Again the function y=cosecx has a period of 2π or 360∘ , i.e., the value of cosecx repeats after an interval of 2π or 360∘ . Therefore we calculate the given period using the intervals. After that we use the trigonometric formulas and we get the required value.
Complete step by step answer:
We know that the function y=cosecx has a period of 2π or 360∘ , i.e., the value of cosecx repeats after an interval of 2π or 360∘ .
First we draw the graph of y=cosecx
Now the given data 120∘=90∘+30∘
Therefore csc(−120)
Using the property csc(−x)=−cscx , we get
−csc(120)
We can write the above statement as,
=−csc(90+30)
We know that cscx=sinx1 , use this property and we get
=−sin(90+30)1
We know that the property of trigonometric that is sin(90+x)=cosx
Use this in the above function and we get
=−cos301
From the value table we know the value of cos30=23=sin60 , put this in above equation and we get
=−231
Simplifying and we get
=−32
Therefore our required answer is csc(−120)=−32 .
Note: Note that formulas which is very important and try to remember all the times
1.sinx=cscx1,cosx=secx1,tanx=cotx1
2.sin2x+cos2x=1
3.sec2x−tan2x=1
4.csc2x−cot2x=1
5.sin(−x)=−sinx
6.cos(−x)=cosx
7.tan(−x)=−tanx
8.sin(2nπ±x)=sinx , period 2π
9.cos(2nπ±x)=cosx , period 2π
10.tan(nπ±x)=tanx , period π
WE also have to know about the sign conversion ,
In the first quadrant we know all the trigonometric functions are positive. In the second quadrant sine function is positive and others are negative. The third quadrant tangent is positive and in the fourth quadrant cos is positive. At least we must know about the trigonometric function value table. We have all the basic values of all trigonometric functions.