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Question: How do you find the sum of the infinite geometric series \(0.5 + 0.05 + 0.005 + ...\) ?...

How do you find the sum of the infinite geometric series 0.5+0.05+0.005+...0.5 + 0.05 + 0.005 + ... ?

Explanation

Solution

In a geometric progression, each term is multiplied by a common ratio to get the next term. The terms of such series is given by, a,ar,ar2,...a,{\kern 1pt} {\kern 1pt} {\kern 1pt} ar,{\kern 1pt} {\kern 1pt} {\kern 1pt} a{r^2},... , where rr is the common ratio. We can use the formula to find the sum of the series upto nn terms given by, Sn=a(1rn)(1r){S_n} = \dfrac{{a(1 - {r^n})}}{{(1 - r)}}.

Formula used:
Sn=a(1rn)(1r){S_n} = \dfrac{{a(1 - {r^n})}}{{(1 - r)}}
S=a(1r){S_\infty } = \dfrac{a}{{(1 - r)}}

Complete step by step solution:
We are given a series 0.5+0.05+0.005+...0.5 + 0.05 + 0.005 + ...
We are given that this series is a Geometric Progression.
We can find the common ratio of the series by dividing the consecutive terms.
We can calculate the common ratio as r=0.050.5=0.0050.05=0.1r = \dfrac{{0.05}}{{0.5}} = \dfrac{{0.005}}{{0.05}} = 0.1
Thus, the given series is a Geometric Progression (GP) with common ratio r=0.1r = 0.1
Now we can use the formula to find the sum of the series up to nn terms given by, Sn=a(1rn)(1r){S_n} = \dfrac{{a(1 - {r^n})}}{{(1 - r)}}.
We have to find the sum of the series up to infinite terms.
Since r<1r < 1, as nn \to \infty we can say that rn0{r^n} \to 0. Therefore, (1rn)1(1 - {r^n}) \to 1.
Thus, the formula for sum of the infinite geometric series becomes,
S=a(1r){S_\infty } = \dfrac{a}{{(1 - r)}}
where, S{S_\infty } is the sum of the infinite series
aa is the first term of the series
rr is the common ratio
In the given series, a=0.5a = 0.5 and r=0.1r = 0.1
Putting all the values in the above formula, we get,

S=0.5(10.1) S=0.50.9 S=590.556  {S_\infty } = \dfrac{{0.5}}{{(1 - 0.1)}} \\\ \Rightarrow {S_\infty } = \dfrac{{0.5}}{{0.9}} \\\ \Rightarrow {S_\infty } = \dfrac{5}{9} \approx 0.556 \\\

Thus, the sum of the given infinite series is 590.556\dfrac{5}{9} \approx 0.556.

Note: We can find the sum of the geometric series up to \infty terms using the formula only when the absolute value of the common ratio is less than 11, i.e. r<1\left| r \right| < 1. For r>1\left| r \right| > 1, we can only calculate sums up to nn terms where nn is a finite natural number. We can calculate the sum of the series without knowing all the terms, we only need at most three terms to calculate the common ratio.