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Question: How do you find the sum of the arithmetic series \(34 + 30 + 26 + .. + 2?\)...

How do you find the sum of the arithmetic series 34+30+26+..+2?34 + 30 + 26 + .. + 2?

Explanation

Solution

First find the common difference of the given arithmetic series by subtracting two successive terms. After finding the common difference “d” of the given arithmetic series use the below sum formula of arithmetic series in order to find the sum of the given arithmetic series: Sn=n2[2a+(n1)d],  where  Sn{S_n} = \dfrac{n}{2}\left[ {2a + \left( {n - 1} \right)d} \right],\;{\text{where}}\;{S_n} presents the sum of an arithmetic series up to nn terms having first term equals aa and common difference dd

Complete step by step solution:
To find the sum of the arithmetic series 34+30+26+..+234 + 30 + 26 + .. + 2 we will find the sum with help of formula for sum of nn numbers in arithmetic series, which is given as
Sn=n2[2a+(n1)d]{S_n} = \dfrac{n}{2}\left[ {2a + \left( {n - 1} \right)d} \right]
Where Sn{S_n} is the sum of nn terms in an arithmetic series having aa as its first term and dd as a common difference.
Common difference (d)(d) can be determine by the subtraction of any two successive terms in series
d=2630=4\Rightarrow d = 26 - 30 = - 4
So we get the common difference d=4d = - 4
In the arithmetic series 34+30+26+..+234 + 30 + 26 + .. + 2, we can see first term is a=34a = 34
Also in an arithmetic series rth{r^{{\text{th}}}} term is given as ar=a+(n1)d{a_r} = a + (n - 1)d
We will use this formula to find the value of nn
We know that 22 is the last term in 34+30+26+..+234 + 30 + 26 + .. + 2
It can be written as
2=34+(n1)(4) 2=344n+4 4n=382 4n=36 n=9  \Rightarrow 2 = 34 + (n - 1)( - 4) \\\ \Rightarrow 2 = 34 - 4n + 4 \\\ \Rightarrow 4n = 38 - 2 \\\ \Rightarrow 4n = 36 \\\ \Rightarrow n = 9 \\\
Now putting all the values to get sum,
S9=92[2×34+(91)(4)] =92[6832] =9×362 =162  {S_9} = \dfrac{9}{2}\left[ {2 \times 34 + \left( {9 - 1} \right)( - 4)} \right] \\\ = \dfrac{9}{2}\left[ {68 - 32} \right] \\\ = \dfrac{{9 \times 36}}{2} \\\ = 162 \\\
\therefore sum of the arithmetic series 34+30+26+..+2  is  16234 + 30 + 26 + .. + 2\;{\text{is}}\;162
Formula used:
1. Sum of Arithmetic series, Sn=n2[2a+(n1)d]{S_n} = \dfrac{n}{2}\left[ {2a + \left( {n - 1} \right)d} \right]
2. Formula for rth{r^{{\text{th}}}} term, ar=a+(n1)d{a_r} = a + (n - 1)d

Note: Common difference tells about the nature of an arithmetic series, if common difference is positive then arithmetic series is increasing and if it is negative then arithmetic series is decreasing. The above formula is invalid for finding the sum of infinite arithmetic series.