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Question

Question: How do you find the slope of\[y = 2x - 1?\]...

How do you find the slope ofy=2x1?y = 2x - 1?

Explanation

Solution

In this type of question we need to know the basic equation of the straight line. Also, we need to know the meaning of each term. That is we need to know which is slope value and which is intercept value. To find the slope from the given equation we need to compare the given equation with the basic straight line equation.

Complete step by step solution:
The equation in the given question is shown below,
y=2x1(1)y = 2x - 1 \to \left( 1 \right)

To solve the given problem we need to know the basic form of the straight-line equation.

The basic form of the straight-line equation is given below,
y=mx+c(2)y = mx + c \to \left( 2 \right)

Here, yyis the function ofxx,
mmis the slope of the straight line,
ccis the intercept ofyy.

To find the value of slope compare the equations(1)\left( 1 \right) and(2)\left( 2 \right),
(1)y=2x1\left( 1 \right) \to y = 2x - 1
(2)y=mx+c\left( 2 \right) \to y = mx + c

By comparing the constant terms in the above mentioned two equations, we get

\-1 c \- 1 \\\ c \\\

So, the value ofccis1 - 1, that is the intercept ofyyis equal to1 - 1.

By comparing thexxterms in the equation(1)\left( 1 \right) and(2)\left( 2 \right), we get

2x mx 2x \\\ mx \\\

So, the value of m is equal to22. That is the value of the slope is22.

So, the final answer is, Slope=22

Note: To solve this type of question we would remember the basic equation of the straight line. To find the value of slope we would compare the given equation with the basic form of the straight line. Remember thatmm is the slope of a straight line andccis the intercept of the straight line. Note that the intercept value must be a constant.