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Question

Question: How do you find the slope of the line parallel to and perpendicular to \(y=3x-4\) ?...

How do you find the slope of the line parallel to and perpendicular to y=3x4y=3x-4 ?

Explanation

Solution

To find the slope of the line parallel to y=3x4y=3x-4 , we have to express the given equation in slope-intercept form. We know that slope-intercept form is given as
y=mx+cy=mx+c , where m is the slope and c is the y-intercept. We know that a line parallel to another line will have the same slopes. A line perpendicular to another line, say, y=mx+cy=mx+c will have a negative of the reciprocal of the slope of y=mx+cy=mx+c . We can denote this as mp=1m{{m}_{p}}=-\dfrac{1}{m} .

Complete step by step solution:
We have to find the slope of the line parallel to and perpendicular to y=3x4y=3x-4 . First, let us express the given equation in slope-intercept form. We know that slope-intercept form is given as
y=mx+cy=mx+c , where m is the slope and c is the y-intercept.
Let us compare the above equation with y=3x4y=3x-4 . We can see that m=3,c=4m=3,c=-4 .
We know that a line parallel to another line will have the same slopes. Hence, the slope of the line parallel to y=3x4y=3x-4 will be 3.
We know that a line perpendicular to another line, say, y=mx+cy=mx+c will have a negative of the reciprocal of the slope of y=mx+cy=mx+c . We can denote this as mp=1m{{m}_{p}}=-\dfrac{1}{m} .
mp=13\Rightarrow {{m}_{p}}=-\dfrac{1}{3}

Note: Students have a chance to make mistakes by writing the slopes for parallel line as mp=1m{{m}_{p}}=-\dfrac{1}{m} and that for perpendicular line as m. They must always convert the given equation into slope-intercept form.