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Question: How do you find the slope of \(( - 4,{\kern 1pt} {\kern 1pt} {\kern 1pt} - 1)\), \(( - 2,{\kern 1pt}...

How do you find the slope of (4,1)( - 4,{\kern 1pt} {\kern 1pt} {\kern 1pt} - 1), (2,5)( - 2,{\kern 1pt} {\kern 1pt} {\kern 1pt} - 5)?

Explanation

Solution

We will get a straight line joining the given two points. The slope of the line is the change in the value of yy with respect to xx. For a straight line, if two points A(x1,y1)A({x_1},{\kern 1pt} {\kern 1pt} {\kern 1pt} {y_1}) and B(x2,y2)B({x_2},{\kern 1pt} {\kern 1pt} {\kern 1pt} {y_2}) are situated on the line, then by using the slope formula we can calculate the slope (m) as, m=y2y1x2x1m = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}.

Complete step by step solution:
We have to find the slope of the line passing through the points (4,1)( - 4,{\kern 1pt} {\kern 1pt} {\kern 1pt} - 1), (2,5)( - 2,{\kern 1pt} {\kern 1pt} {\kern 1pt} - 5).
As we already know two points on the line, we will use the slope formula to find the slope of the line.
The slope formula is given by m=y2y1x2x1m = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}
where, A(x1,y1)A({x_1},{\kern 1pt} {\kern 1pt} {\kern 1pt} {y_1}) and B(x2,y2)B({x_2},{\kern 1pt} {\kern 1pt} {\kern 1pt} {y_2}) are the two points on the line
mm is the slope of the line
From the given points we can write,
x1=4{x_1} = - 4, y1=1{y_1} = - 1, x2=2{x_2} = - 2 and y2=5{y_2} = - 5
Putting the values in the formula we get,
m=y2y1x2x1 m=(5)(1)(2)(4) m=5+12+4 m=42=2  \Rightarrow m = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}} \\\ \Rightarrow m = \dfrac{{( - 5) - ( - 1)}}{{( - 2) - ( - 4)}} \\\ \Rightarrow m = \dfrac{{ - 5 + 1}}{{ - 2 + 4}} \\\ \Rightarrow m = \dfrac{{ - 4}}{2} = - 2 \\\
Thus, the value of mm is 2 - 2.

Hence, the slope of the line passing through (4,1)( - 4,{\kern 1pt} {\kern 1pt} {\kern 1pt} - 1) and (2,5)( - 2,{\kern 1pt} {\kern 1pt} {\kern 1pt} - 5) is 2 - 2.

Note: For a line making obtuse angle with the x-axis, the slope is negative as the behavior of yy is opposite to that of xx, i.e. the value of yy decreases for increase in the value of xx and the value of yy increases for decrease in the value of xx. We can also find the slope of the line by first calculating the equation of the line passing through the given points and then using the slope-intercept formula y=mx+cy = mx + c, where mm is the slope of the line and cc is the y-intercept. The choice of the method depends on the information given in the question and the ease of solution.