Question
Question: How do you find the slope of \(( - 4,{\kern 1pt} {\kern 1pt} {\kern 1pt} - 1)\), \(( - 2,{\kern 1pt}...
How do you find the slope of (−4,−1), (−2,−5)?
Solution
We will get a straight line joining the given two points. The slope of the line is the change in the value of y with respect to x. For a straight line, if two points A(x1,y1) and B(x2,y2) are situated on the line, then by using the slope formula we can calculate the slope (m) as, m=x2−x1y2−y1.
Complete step by step solution:
We have to find the slope of the line passing through the points (−4,−1), (−2,−5).
As we already know two points on the line, we will use the slope formula to find the slope of the line.
The slope formula is given by m=x2−x1y2−y1
where, A(x1,y1) and B(x2,y2) are the two points on the line
m is the slope of the line
From the given points we can write,
x1=−4, y1=−1, x2=−2 and y2=−5
Putting the values in the formula we get,
⇒m=x2−x1y2−y1 ⇒m=(−2)−(−4)(−5)−(−1) ⇒m=−2+4−5+1 ⇒m=2−4=−2
Thus, the value of m is −2.
Hence, the slope of the line passing through (−4,−1) and (−2,−5) is −2.
Note: For a line making obtuse angle with the x-axis, the slope is negative as the behavior of y is opposite to that of x, i.e. the value of y decreases for increase in the value of x and the value of y increases for decrease in the value of x. We can also find the slope of the line by first calculating the equation of the line passing through the given points and then using the slope-intercept formula y=mx+c, where m is the slope of the line and c is the y-intercept. The choice of the method depends on the information given in the question and the ease of solution.