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Question: How do you find the slope given \(\left( 3,2 \right),\ \left( 5,12 \right)\)?...

How do you find the slope given (3,2), (5,12)\left( 3,2 \right),\ \left( 5,12 \right)?

Explanation

Solution

From the question given we have been asked to find the slope of the two points they are (3,2), (5,12)\left( 3,2 \right),\ \left( 5,12 \right). We know that the formula for the slope of two points if (x1,y1), (x2,y2)\left( {{x}_{1}},{{y}_{1}} \right),\ \left( {{x}_{2}},{{y}_{2}} \right) then the slope of these two points is m=y2y1x2x1m=\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}. By this formula we will get the slope of the two points.

Complete step-by-step solution:
From the given question we have been asked to find the slope of the two points
(3,2), (5,12)\Rightarrow \left( 3,2 \right),\ \left( 5,12 \right)
As we know that the formula for the slope of two points if (x1,y1) (x2,y2)\left( {{x}_{1}},{{y}_{1}} \right)\ \left( {{x}_{2}},{{y}_{2}} \right) then the slope of these two points is
m=y2y1x2x1\Rightarrow m=\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}
By comparing the given with the general points we will get the values as
Here the values are
x1=3\Rightarrow {{x}_{1}}=3
x2=5\Rightarrow {{x}_{2}}=5
y1=2\Rightarrow {{y}_{1}}=2
y2=12\Rightarrow {{y}_{2}}=12
From this we can find the slope
By substituting the above values in the formula of slope we will get
m=y2y1x2x1\Rightarrow m=\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}
By substituting the values in their respective positions or places we will get,
m=12253\Rightarrow m=\dfrac{12-2}{5-3}
By simplifying further, we will get,
m=102\Rightarrow m=\dfrac{10}{2}
By simplifying further, we will get,
m=5\Rightarrow m=5
Therefore, the slope of the given two points (3,2), (5,12)\left( 3,2 \right),\ \left( 5,12 \right) is 55.

Note: Students should know the basic formulas of two-dimensional coordinate geometry. Some of the important formulas by using slope are, if a line equation is y=mx+cy=mx+c then the slope of the line is ”m”. if a line passes through the two points they are (x1,y1), (x2,y2)\left( {{x}_{1}},{{y}_{1}} \right), \ \left( {{x}_{2}},{{y}_{2}} \right) then the line equation is yy1=y2y1x2x1(xx1)y-{{y}_{1}}=\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}\left( x-{{x}_{1}} \right) where y2y1x2x1\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}} is the slope of the line.