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Question

Question: How do you find the slope for \[2x + 3y = 12\]?...

How do you find the slope for 2x+3y=122x + 3y = 12?

Explanation

Solution

Here, we have to find the slope of the given equation of the line. We will compare the given equation of the line with the standard equation of a line to find the coefficients of the variables and the constant term. Then using these and the slope formula, we will find the required slope of the line.

Formula used:
Slope of the equation of line is given by the formula m=abm = - \dfrac{a}{b}

Complete step by step solution:
We are given an equation of line 2x+3y=122x + 3y = 12.
The standard equation of line is of the form ax+by=cax + by = c.
Comparing the given equation of line with the standard equation of line, we get a=2;b=3;c=12;a = 2;b = 3;c = 12;
Now, we will find the slope for the equation of line 2x+3y=122x + 3y = 12.
Slope of the equation of line is given by the formula m=abm = - \dfrac{a}{b}
By substituting the values of a=2a = 2 and b=3b = 3 in the formula, we get
m=23m = - \dfrac{2}{3}

Therefore, the slope of the equation of line 2x+3y=122x + 3y = 12 is 23 - \dfrac{2}{3}.

Additional Information:
We know that slope is defined as the ratio of change in the y axis to the change in the xx axis. A slope can be represented in the parametric form and in the point form. A point crossing the xx-axis is called xx-intercept and A point crossing the y-axis is called the y-intercept. The slope of a line is used to calculate the steepness of a line. We know that the Slope of a line is used to find the equation of a line.

Note:
We can also find the slope using the slope- intercept form. Slope- Intercept Form of the equation of line is y=mx+cy = mx + c where mm is the slope and cc is the yy-intercept. Thus, the given equation is written in the slope- intercept form, we get
2x+3y=122x + 3y = 12
By rewriting the given equation in the slope-intercept form, we get
3y=2x+12\Rightarrow 3y = - 2x + 12
y=23x+123\Rightarrow y = \dfrac{{ - 2}}{3}x + \dfrac{{12}}{3}
By simplifying the equation, we get
y=23x+4\Rightarrow y = \dfrac{{ - 2}}{3}x + 4
By comparing with equation of line in slope-intercept form, we getm=23m = - \dfrac{2}{3} andc=4c = 4
Therefore, the slope of the equation of line2x+3y=122x + 3y = 12is23 - \dfrac{2}{3}.