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Question: How do you find the slope and y intercept for \( - 5x + 3y = - 9\)?...

How do you find the slope and y intercept for 5x+3y=9 - 5x + 3y = - 9?

Explanation

Solution

The slope of a line in graph is the change in the value of yy with respect to xx in the equation, i.e. m=y2y1x2x1m = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}. The y intercept is the point at which the line cuts the y-axis which we can find by putting x=0x = 0. Alternatively, we can find the slope of the line and the y intercept simultaneously by using the slope-intercept formula wherein we write the given equation in the form y=mx+cy = mx + c, where mm is the slope of the line and cc is the y-intercept.

Complete step by step solution:
We have to find the slope and y intercept of the line given by the equation 5x+3y=9 - 5x + 3y = - 9.
We will use the slope-intercept formula to find the slope of the line.
The slope-intercept formula is given by y=mx+cy = mx + c.
We can rewrite the given equation in the form,
5x+3y=9 3y=5x9 y=53x93 y=53x3  \Rightarrow - 5x + 3y = - 9 \\\ \Rightarrow 3y = 5x - 9 \\\ \Rightarrow y = \dfrac{5}{3}x - \dfrac{9}{3} \\\ \Rightarrow y = \dfrac{5}{3}x - 3 \\\
On comparing with the standard form of the slope-intercept formula, we observe that
m=53m = \dfrac{5}{3} and c=3c = - 3
Thus, the slope of the given line is 53\dfrac{5}{3} and the y-intercept is 3 - 3.
Hence, the slope of the line 5x+3y=9 - 5x + 3y = - 9 is 53\dfrac{5}{3}and it cuts the y-axis at the point (0,3)(0,{\kern 1pt} {\kern 1pt} {\kern 1pt} - 3).

Thus, the slope of the given line is 53\dfrac{5}{3} and the y-intercept is 3 - 3.

Note: For a line making obtuse angle with the x-axis, the slope is negative as the behavior of yy is opposite to that of xx, i.e. the value of yy decreases for increase in the value of xx and the value of yy increases for decrease in the value of xx. We can also find the y intercept of the line by putting x=0x = 0 in the equation as when the line is cutting the y-axis the value of xx is 00.